[英]Can't cross compile c++ class with sqlite included (undefined reference) on linux (i686-w64-mingw32-g++)
[英]Can't compile in Linux with curl - undefined reference
我正在嘗試使用curl lib在Linux(ubuntu)中編譯c ++示例但是我得到了對'curl_easy_init'的未定義引用
編譯命令:
gcc -L/usr/local/lib -lcurl -I/usr/local/include -o request request.cpp
結果:
/tmp/ccZwDiCf.o: In function 'main':<br>
request.cpp:(.text+0xa): undefined reference to 'curl_easy_init'<br>
request.cpp:(.text+0x31): undefined reference to 'curl_easy_setopt'<br>
request.cpp:(.text+0x3d): undefined reference to 'curl_easy_perform'<br>
request.cpp:(.text+0x54): undefined reference to 'curl_easy_strerror'<br>
request.cpp:(.text+0x7b): undefined reference to 'curl_easy_cleanup'<br>
collect2: ld returned 1 exit status
碼:
#include <curl/curl.h>
#include <stdio.h>
int main(int argc, char* argv[]){
CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
curl_easy_setopt(curl, CURLOPT_URL, "http://google.com");
res = curl_easy_perform(curl);
if(res!=CURLE_OK)
fprintf(stderr, "curl_easy_perform() failed: %s\n",curl_easy_strerror(res));
curl_easy_cleanup(curl);
}
return 0;
}
回答只是為了結束這個問題。
對於resumate,您必須將-lcurl選項放在編譯命令行的末尾。
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