如何解析Objective-C中的對象數組？

Question

來自C ++，這是我的問題：

我創建了這種類型的對象：

    Size *one = [[Size alloc] initWithX: 3 andY: 1];
    Size *two = [[Size alloc] initWithX: 4 andY: 7];
    // etc...
    Size *thirtythree = [[Size alloc] initWithX: 5 andY: 9];

（使用@property int x; ＆ @property int y;對於每個對象..）

我已經存儲在數組中，如下所示：

NSArray *arrayOfSizes;

arrayOfSizes = [NSArray arrayWithObjects:one,two,three,four,five,six,
                seven,eight,nine,ten,eleven,twelve,thirteen,
                fourteen,fifteen,sixteen,seventeen,eighteen,
                nineteen,twenty,twentyone,twentytwo,
                twentythree,twentyfour,twentyfive,twentysix,
                twentyseven,twentyeight,twentynine,thirty,
                thirtyone,thirtytwo,thirtythree nil];

現在我有一個類型的單個對象：

Myobject *myObject = [[Myobject alloc] initWithX: 5 andY: 3];

也有@property int x; ＆ @property int y; ...

我想將它的值與數組中找到的對象的值進行比較，直到我找到一個具有相似值的數組對象。但我不知道如何在Obj-C中這樣做。 （在c ++中，我只是使用vector v;使用v.size();以及v[x]; .. v.size(); ...我想..）

這就是我要找的東西.. :)

while( !wholeOfArrayOfSizesChecked && !found)
{
    if ( // x & y of object in array is equal to x & y of myObject )
    {
        found = YES;
    }
    else if( // whole of array checked)
    {
       wholeOfArrayOfSizesChecked = YES;
    }
    else
    { 
      //move on to the next object of the array..
    }
}

在此先感謝您的幫助！

Answer 1

好吧，你可以在數組上使用快速枚舉 。 像這樣的東西：

Myobject *myObject = [[Myobject alloc] initWithX: 5 andY: 3];

for (Size *s in arrayOfSizes)
{
    if (s.x == myObject.x && s.y == myObject.y)
    {
        // Found one
        // Do something useful...
        break;
    }
}

Answer 2

另一個：

NSUInteger index = [arrayOfSizes indexOfObjectPassingTest:
    ^BOOL(Size *s, NSUInteger idx, BOOL *stop)
    {
        return (s.x == myObject.x) && (s.y == myObject.y);
    }
];

if (index != NSNotFound) {
    id object = [arrayOfSizes objectAtIndex:index];
}

Answer 3

怎么一個for-in循環？

for (Size *item in array) {
   // compare 'item' to myObject
   if (/* equal condition here */) break;
}

Answer 4

嘗試這樣的事情：

for (int i = 0; i < [arrayOfSizes size]; i++)
{
  Size *current = (Size *)[arrayOfSizes objectAtIndex:i];
  if (myObject.x == current.x && myObject.y == current.y)
  {
    // found
    break;
  }
}

Answer 5

-(BOOL) isSize:(Size*)size equalToMyObject:(MyObject*)object{
    return (size.x == object.x) && (size.y == object.y);
}

//In some method where you are checking it:
for (Size* size in arrayOfSizes){
        if ([self isSize:size equalToMyObject:myObject]){
            //You found it! They're equal!
            break;
        }
}

Answer 6

只是為了使用你給定的結構。 有更聰明的方法，但:)

wholeOfArrayOfSizesChecked = NO; 
int currObj = 0  
while( !wholeOfArrayOfSizesChecked && !found)
{
    Size *current = (Size *)[arrayOfSizes objectAtIndex:i];
    if (myObject.x == current.x && myObject.y == current.y)
    {
        found = YES;
    }
    else if(currObj == [arrayOfSizes count] -1 )
    {
       wholeOfArrayOfSizesChecked = YES;
    }
    else
    { 
      currObj++;
    }
}