我如何配置Spring 2.5.6 + eclipseLink + Weblogic 10.3

Question

    <bean id="configProperties" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
    <property name="placeholderPrefix" value="${" />
    <property name="placeholderSuffix" value="}" />
    <property name="locations">
        <value>classpath:ddes/config.properties</value>
    </property>
</bean>

<bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
    <property name="jndiName" value="${datasource}"/>
    <property name="resourceRef" value="true"/>
</bean>

<context:load-time-weaver weaver-class="org.springframework.instrument.classloading.weblogic.WebLogicLoadTimeWeaver"/>

<bean id="PersistenceUnit" class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
    <property name="defaultDataSource" ref="dataSource"/>
    <property name="class">
    <!--LIST BEANS-->
        <value>....</value>
    </property>
</bean>

<bean id="jpaVendorAdapter" class="org.springframework.orm.jpa.vendor.EclipseLinkJpaVendorAdapter">
    <property name="databasePlatform" value="org.eclipse.persistence.platform.database.OraclePlatform"/>
    <property name="generateDdl" value="true"/>
    <property name="showSql" value="true"/>
</bean>

<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="jpaVendorAdapter" ref="jpaVendorAdapter"/>
    <property name="persistenceUnitManager" ref="PersistenceUnit"/>
    <property name="persistenceUnitName" ref="Persistence-ejbPU"/>
    <property name="persistenceProvider" ref="org.eclipse.persistence.jpa.PersistenceProvider"/>
</bean>

<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager">
    <property name="transactionManager" ref="entityManagerFactory"/>
</bean>

實行

@CallByReference
@Stateless(mappedName = "cliente") 
public class ClienteDAOBean implements ClienteDAOLocal, ClienteDAORemote {


    @PersistenceUnit(unitName = "Persistence-ejbPU")
    private EntityManagerFactory emf;

    public Clientes find(Integer codCliente) throws Exception {
        Clientes cliente = null;
        EntityManager em = emf.createEntityManager();
        try {
            javax.persistence.Query q = em.createNamedQuery("Clientes.findByCodCliente").setParameter("codCliente", codCliente);
            cliente = (Clientes) q.getSingleResult();
        } catch (Exception e) {
            throw e;
        } finally {
            em.close();
            return cliente;
        }
    }
}

錯誤的日志顯示錯誤：

范圍Persistence-ejbPU.jar中沒有名為“ Persistence-ejbPU”的持久性單元

以前使用的是persistence.xml文件，但需要動態獲取數據源的名稱

Answer 1

只需將ref替換為value。 采用：

 <property name="persistenceUnitName" value="Persistence-ejbPU" />

代替：

<property name="persistenceUnitName" ref="Persistence-ejbPU"/>

如果仍然有問題，那么我將實現我自己的LocalContainerEntityManagerFactoryBean類，該類從AbstractEntityManagerFactoryBean擴展而來，因此您可以覆蓋setPersistenceUnitName然后查看發生了什么。