使用jquery從Json獲取數據

Question

我有以下json數據，這些數據位於url http://localhost/stock/index.php/masterfiles/itemgriddata

[{"name":"asdasd","code":"123","id":"1","unit":"Nos","purprice":"25000"},{"name":"Item2","code":"1235","id":"2","unit":"Nos","purprice":"0"}]

我想獲取id等於1的name和code的值，並使用jquery將它們存儲為變量。

我知道有一種方法，

$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  console.log(data);
});

但我不知道如何實現。 誰能幫我找到解決方案？

Answer 1

$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  $.each(data, function(index, val) {
      if( val.id == '1'){
        var name = val.name,
            code = val.code,
            unit = val.unit,
            purprice = val.purprice,
            id = val.id;
      }
  })
});

但是，如果要將所有結果存儲在數組中，則：

var dataarr = [];
$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  $.each(data, function(index, val) {
      if( val.id == '1'){
        dataarr.push(
            val.name,
            val.code,
            val.unit,
            val.purprice,
            val.id;
       );
  })
});

有關更多詳細信息，請參見doco 。

Answer 2

您可以遍歷數組並檢查ID為“ 1”的對象是否為

arr = [{"name":"asdasd","code":"123","id":"1","unit":"Nos","purprice":"25000"},{"name":"Item2","code":"1235","id":"2","unit":"Nos","purprice":"0"}]

$.each(arr, function(i,ele){
 if (ele.id =="1"){
  alert(ele.name)
  alert(ele.code)
 }
});

Answer 3

您可以嘗試如下操作：

$.getJSON('http://localhost/stock/index.php/masterfiles/itemgriddata', function(data) {
  var results = [];

  $.each(data, function(key, val) {
    if (val.id === "1") {
        results.push(val.name);
        results.push(val.code);
    }
  });
  // Then you can do whatever you want to do with results
});

Answer 4

請閱讀此鏈接上可用的文檔

jQuery.getJSON（）