[英]Unable to retrieve results from database using a variable gained from a query in CakePHP 2
我在構建某件東西時遇到了問題。
我有兩個表,一個是作業表表,另一個是作業數據表。 作業表表存儲有關作業號,工人等的信息。“作業數據”表存儲作業號(鏈接到“作業表”表)以及與之相關的作業等。 因此,例如:
Job Sheet
---------------------------
| ID | Jobnum | Worker |
---------------------------
| 1 | 1234 | J.Bloggs |
| 2 | 5678 | J.Smith |
---------------------------
Job Data
----------------------------
| ID | Jobnum | Work |
----------------------------
| 1 | 1234 | Light bulb |
| 2 | 1234 | Painting |
| 3 | 1234 | Decorating |
| 4 | 5678 | Wood Work |
| 5 | 5678 | Cleaning |
----------------------------
我的問題是,當我要在屏幕上打印作業表時,我希望能夠打印作業表的詳細信息,然后為每個作業表打印其相關數據,如下所示:
Job Sheets To Be Printed
--------------------------------------------------------
Job Sheet ID - 1
Job Number - 1234
Worker - J.Bloggs
Work Undertaken
---------------
Light Bulb
Painting
Decorating
***********
Job Sheet ID - 2
Job Number - 5678
Worker - J.Smith
Work Undertaken
---------------
Wood Work
Cleaning
我的問題是,盡管我可以打印作業表詳細信息(名稱等),但它只會與數據庫中的一組記錄一起返回,並將它們放入每個作業表中。 因此,即使第一個作業表中的數據應該具有自己的數據,它也會顯示在第二個作業表中。
我在Controller中的代碼是這樣的:
$jobsheets = $this->Jobsheet->find('all', array('conditions' => array('Jobsheet.contract' => $contractid), 'recursive' => 2));
$this->set('jobsheets', $jobsheets);
foreach ($jobsheets as $js) {
$jobnum[] = $js['Jobsheet']['jobnum'];
}
print_r($jobnum);
foreach ($jobnum as $jn) {
// Job Data
$jobrec = $this->Jobdata->find('all', array('conditions' => array('Jobdata.jobsheetid' => $jn), 'recursive' => 2));
$this->set('jobrec', $jobrec);
}
在視圖中,我有以下代碼:
<?php foreach ($jobsheets as $jobsheet) { ?>
<p>Job Sheet ID - <?php echo $jobsheet['Jobsheet']['id']; ?></p>
<p>Job Number - <?php echo $jobsheet['Jobsheet']['jobnum']; ?></p>
<p>Worker - <?php echo $jobsheet['Jobsheet']['worker']; ?></p>
<p>Work Undertaken</p>
<?php foreach ($jobrec as $jb) { ?>
<p><?php echo $jb['Jobdata']['work'];?></p>
<?php } } ?>
因此,目前,它顯示以下內容:
Job Sheets To Be Printed
--------------------------------------------------------
Job Sheet ID - 1
Job Number - 1234
Worker - J.Bloggs
Work Undertaken
---------------
Light Bulb
Painting
Decorating
***********
Job Sheet ID - 2
Job Number - 5678
Worker - J.Smith
Work Undertaken
---------------
Light Bulb
Painting
Decorating
我該怎么做才能解決此問題?
做出控制上的改變
foreach ($jobnum as $jn) {
// Job Data
$jobrec[] = $this->Jobdata->find('all', array('conditions' => array('Jobdata.jobsheetid' => $jn), 'recursive' => 2));
$this->set('jobrec', $jobrec);
}
而這種改變
<?php $i=0; ?>
<?php foreach ($jobsheets as $jobsheet) { ?>
<p>Job Sheet ID - <?php echo $jobsheet['Jobsheet']['id']; ?></p>
<p>Job Number - <?php echo $jobsheet['Jobsheet']['jobnum']; ?></p>
<p>Worker - <?php echo $jobsheet['Jobsheet']['worker']; ?></p>
<p>Work Undertaken</p>
<?php foreach ($jobrec[$i] as $jb) { ?>
<p><?php echo $jb['Jobdata']['work'];?></p>
<?php }
$i++;
} ?>
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