[英]Cannot Instantiate Type in generics
我有這門課
public class Tree<T> {
//List of branches for this tree
private List<Tree<? super T>> branch = new ArrayList<Tree<? super T>>();
public Tree(T t){ this.t = t; }
public void addBranch(Tree< ? super T> src){ branch.add(src); }
public Tree<? extends T> getBranch(int branchNum){
return (Tree<? extends T>) branch.get(branchNum);
}
private T t;
}
我正在嘗試使用此類創建一個變量
public static void main(String[] args){
Tree<? super Number> num2 = new Tree<? super Number>(2);
}
它給了我這個錯誤
Cannot instantiate the type Tree<? super Number>
雖然實例化泛型應該用相應的對象替換。
例如:
Tree<Integer> num2 = new Tree<Integer>(2);
通配符?
創建新實例時無法使用。 您應該將代碼更改為類似的代碼
import java.util.ArrayList;
import java.util.List;
public class Test1 {
public static void main(String[] args){
Tree<? super Number> num2 = new Tree<Number>(2);
num2.addBranch(new Tree<Number>(1));
Tree<? super Number> num3 = (Tree<? super Number>) num2.getBranch(0);
System.out.println(num3);
}
}
class Tree<T> {
//List of branches for this tree
private List<Tree<? super T>> branch = new ArrayList<Tree<? super T>>();
public Tree(T t){ this.t = t; }
public void addBranch(Tree<Number> src){ branch.add((Tree<? super T>) src); }
public Tree<? extends T> getBranch(int branchNum){
return (Tree<? extends T>) branch.get(branchNum);
}
public String toString(){
return String.valueOf(t);
}
private T t;
}
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