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[英]How to incrementally parse (and act on) a large file with Boost.Spirit.Qi?
[英]use Boost.Spirit.Qi to parse into vector
我對靈魂很新。 我試圖使用Qi在我的嵌入式Tcl解釋器中解析CMD命令的參數。 由於一些參數可能會多次使用,我需要一個向量來存儲相同類型的所有參數。
這是我的問題的簡化示例,我嘗試將整數存儲到向量中。
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/phoenix_fusion.hpp>
#include <boost/spirit/include/phoenix_stl.hpp>
#include <boost/spirit/include/support.hpp>
#include <boost/fusion/include/adapt_struct.hpp>
#include <boost/variant/recursive_variant.hpp>
using std::string;
using std::vector;
namespace {
namespace qi = boost::spirit::qi;
namespace phoenix = boost::phoenix;
namespace ascii = boost::spirit::ascii;
struct Argument {
vector<int> svDefine; // macro definitions
};
}
BOOST_FUSION_ADAPT_STRUCT
(
Argument,
(vector<int>, svDefine)
)
namespace {
typedef string::const_iterator SIter;
struct ArgParser : qi::grammar<SIter, Argument(), ascii::space_type> {
qi::rule<SIter, Argument(), ascii::space_type> start;
ArgParser() : ArgParser::base_type(start) {
using phoenix::at_c;
using qi::int_;
using phoenix::push_back;
using namespace qi::labels;
start = +("define" >> int_ [push_back(at_c<0>(_val), _1)]);
}
};
}
使用g ++ 4.5.1 boost 1.51進行編譯會產生錯誤
In file included from /usr/include/boost/spirit/home/phoenix/container.hpp:10:0,
from /usr/include/boost/spirit/home/phoenix.hpp:12,
from /usr/include/boost/spirit/include/phoenix.hpp:13,
from qi_test.cpp:2:
.....
qi_test.cpp:43:64: instantiated from here
/usr/include/boost/spirit/home/phoenix/stl/container/container.hpp:492:40: error: ‘struct boost::fusion::vector<int>’ has no member named ‘push_back’
/usr/include/boost/spirit/home/phoenix/stl/container/container.hpp:492:40: error: return-statement with a value, in function returning 'void'
qi_test.cpp: In static member function ‘static
.....
qi_test.cpp:43:64: instantiated from here
qi_test.cpp:28:509: error: invalid initialization of reference of type boost::fusion::vector<int>&’ from expression of type ‘std::vector<int>’
基本上我很困惑。 不知道出了什么問題。
您在這里混合了兩種類型的矢量模板類:
std::vector
和
boost::fusion::vector
如果你只是省略(注釋掉)
using std::vector;
事情可能會變得非常清楚
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