[英]foreach loop not displaying desired result
嗨,伙計們,謝謝你的時間。 我的問題是關於。
我試圖循環我的文件夾中的圖像以及數據庫中的一個帖子,最終結果如下所示:
發布1
圖片1發布2
圖2郵政3
圖3
目前我得到了這個結果:
發布1
圖片1發布1
圖2發布1
圖片1發布2
圖片1發布2
圖2發布2
圖3
我不想要這個結果。
以下是我的代碼:
$post_info = get_posts();
foreach ($post_info as $info){
$photos = glob('design/img/*');
foreach($photos as $photo) {
echo " <a href='feed.php?pid=".$info['post_id']." ' >
<div style='background:#FFF5C3'> <br> <h2> ".$info['person_mentioned']." </h2>
<h3 style='color: black'> ".$info['body']." </h3> </div> </a>";
echo " <img src='{$photo}' width='285px' height='200px' style='border: 5px solid black'>";
}
}
謝謝你的時間。
試試這個(減去潛在的語言細節,因為我實際上沒有運行來檢查這個代碼)..它基本上是一個常規for循環而不是foreach。
$post_info = get_posts();
$photos = glob('design/img/*');
if (count($post_info) === count($photos)) { // According to your requirement, the counts would be the same
$count = count($post_info);
for ($i = 0; $i < $count; $i++) {
$info = $post_info[$i];
$photo = $photos[$i];
echo " <a href='feed.php?pid=".$info['post_id']." ' > <div style='background:#FFF5C3'> <br> <h2> ".$info['person_mentioned']." </h2>
<h3 style='color: black'> ".$info['body']." </h3> </div> </a>";
echo " <img src='{$photo}' width='285px' height='200px' style='border: 5px solid black'>";
}
}
希望有幫助:)
從get_posts()
獲取圖像詳細信息並刪除內部foreach
循環可能會解決您的問題。
注意:用圖像字段替換$info['something_like_post_image']
。
$post_info = get_posts();
foreach ($post_info as $info) {
//$photos = glob('design/img/*');
//foreach ($photos as $photo) {
echo " <a href='feed.php?pid=" . $info['post_id'] . " ' >
<div style='background:#FFF5C3'> <br> <h2> " . $info['person_mentioned'] . " </h2>
<h3 style='color: black'> " . $info['body'] . " </h3> </div> </a>";
echo " <img src='" . $info['something_like_post_image'] . "' width='285px' height='200px' style='border: 5px solid black'>";
//}
}
UPDATE
/*
* If your images have any naming convention like
* imageFileName = "image_{POST_ID}.jpg"
* then you can use below code (NO DATABASE ENTRY REQUIRED)
* (ie, For post #1 image file would be "image_1.jpg";
* and for post #2 image file would be "image_2.jpg")
*/
$post_info = get_posts();
foreach ($post_info as $info) {
//filename = image_1.jpg or image_2.jpg or...
$photoFileName = 'design/img/' . 'image_' . $info['post_id'] . '.jpg';
if (file_exists($photoFileName)) {
echo " <a href='feed.php?pid=" . $info['post_id'] . " ' >
<div style='background:#FFF5C3'> <br> <h2> " . $info['person_mentioned'] . " </h2>
<h3 style='color: black'> " . $info['body'] . " </h3> </div> </a>";
echo " <img src='" . $photoFileName . "' width='285px' height='200px' style='border: 5px solid black'>";
}
}
注意:您必須與每個帖子保持關系,以對照您的獨特圖像; 否則,在列出時,您將無法通過帖子獲得該獨特圖片。 檢查以下選項以處理這種情況。
更新 - 2
如果您正在尋找循環圖像(沒有任何條件),請使用以下代碼
/*
* If you are looking for a solution that cycles each images
* along with each post, try this one
*/
$post_info = get_posts();
$photos = glob('design/img/*');
$numPhotos = count($photos) + 1;
//assuming your post# starts with 1
$imageId = 1;
foreach ($post_info as $info) {
//cycling
if ($imageId % $numPhotos === 0) {
$imageId = 1;
}
$photoFileName = 'design/img/' . 'image_' . $imageId++ . '.jpg';
//no need of this checking, since you are cycling
//if (!file_exists($photoFileName)) {
// $photoFileName = 'path/to/default/image.jpg';
//}
echo " <a href='feed.php?pid=" . $info['post_id'] . " ' >
<div style='background:#FFF5C3'> <br> <h2> " . $info['person_mentioned'] . " </h2>
<h3 style='color: black'> " . $info['body'] . " </h3> </div> </a>";
echo " <img src='" . $photoFileName . "' width='285px' height='200px' style='border: 5px solid black'>";
}
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