[英]MySQL syntax error while creating a new table
我在下面的代碼中查詢沒有問題。 但是第二個代碼拋出錯誤
您的SQL語法有誤; 檢查與您的MySQL服務器版本相對應的手冊,以在第1行的''附近使用正確的語法
工作代碼:
<?php
mysql_connect("localhost", "","") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
$result =" CREATE TABLE google_csv(
ÿþName varchar(80),
Given_Name varchar(80),
Additional_Name varchar(80),
Family_Name varchar(80),
Yomi_Name varchar(80),
Given_Name_Yomi varchar(80),
Additional_Name_Yomi varchar(80),
Family_Name_Yomi varchar(80),
Name_Prefix varchar(80),
Name_Suffix varchar(80),
Initials varchar(80),
Nickname varchar(80),
Short_Name varchar(80),
Maiden_Name varchar(80),
Birthday varchar(80),
Gender varchar(80),
Location varchar(80),
Billing_Information varchar(80),
Directory_Server varchar(80),
Mileage varchar(80),
Occupation varchar(80),
Hobby varchar(80),
Sensitivity varchar(80),
Priority varchar(80),
Subject varchar(80),
Notes varchar(80),
Group_Membership varchar(80),
E_mail_1___Type int(11),
E_mail_1___Value int(11),
E_mail_2___Type int(11),
E_mail_2___Value int(11),
Phone_1___Type int(11),
Phone_1___Value int(11),
Phone_2___Type int(11),
Phone_2___Value int(11),
Phone_3___Type int(11),
Phone_3___Value int(11),
Address_1___Type int(11),
Address_1___Formatted int(11),
Address_1___Street int(11),
Address_1___City int(11),
Address_1___PO_Box int(11),
Address_1___Region int(11),
Address_1___Postal_Code int(11),
Address_1___Country int(11),
Address_1___Extended_Address int(11),
Website_1___Type int(11),
Website_1___Value int(11)
)";
echo $result;
mysql_query($result);
echo mysql_error();
?>
產生代碼時出錯;
<?php
// GENERATE TABLE FROM FIRST LINE OF CSV FILE
$inputFile = 'google.csv';
$tableName = 'google_csv';
$fh = fopen($inputFile, 'r');
$contents = fread($fh, 5120); // 5KB
fclose($fh);
$fileLines = explode("\n", $contents);
$fieldList = explode(',', $fileLines[0]);
$lastField=count($fieldList)-1;
echo "Total Fields :".count($fieldList)."<br>";
echo "Last Field :".$lastField."<br>";
$result ="CREATE TABLE $tableName(";
for($i = 0; $i < count($fieldList); $i++)
{
if(preg_match('/[1-9]/', $fieldList[$i]))
{
if ($i==$lastField)
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' int(11)';}
else
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' int(11),';}
}
else
{
if($i==$lastField)
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' varchar(80)';}
else
{$result .=str_replace(array(" ",'-'),"_",$fieldList[$i]). ' varchar(80),';}
}
}
$result .=")";
if ($result) {echo $result."<br>".$i."<br>";} else {Echo "Some Problem!";}
mysql_connect("localhost", "","") or die(mysql_error());
mysql_select_db("") or die(mysql_error());
mysql_query($result);
echo mysql_error();
?>
我在第一個代碼中使用此處的$result
輸出,它工作得很好! 第二個代碼在哪里出錯?
$ result回聲給出
創建表google_csv(ÿþNamevarchar(80),Given_Name varchar(80),Additional_Name varchar(80),Family_Name varchar(80),Yomi_Name varchar(80),Given_Name_Yomi varchar(80),Addiveal_Name_Yomi varchar(80) ),名稱前綴varchar(80),名稱_后綴varchar(80),首字母varchar(80),昵稱varchar(80),簡稱varchar(80),Maiden_Name varchar(80),生日varchar(80),性別varchar(80),位置varchar(80),Billing_Information varchar(80),Directory_Server varchar(80),Mileage varchar(80),職業varchar(80),Hobby varchar(80),靈敏度varchar(80),Priority varchar(80),Subject varchar (80),Notes varchar(80),Group_Membership varchar(80),E_mail_1_ 類型int(11),E_mail_1 _Value int(11),E_mail_2_ 類型int(11),E_mail_2 _Value int(11),Phone_1_ 類型int(11) ,Phone_1 _Value int(11),Phone_2_ 類型int(11),Phone_2 _Value int(11),Phone_3_ 類型int(11),Phone_3 _Value int(11),Address_1_ 類型int(11),Address_1 _Formatted int(11),地址_1_ Street int(11),地址 _1 _City int(11),Addr ess_1_ PO_Box int(11),Address_1 _Region int(11),Address_1_ Postal_Code int(11),Address_1 _Country int(11),Address_1_ Extended_Address int(11),Website_1 _Type int(11),Website_1 ___ Value int(11))
看起來這里一切都很好! 但是之后......
這是什么 :
ÿþ
$result ="CREATE TABLE google_csv(ÿþName ....")
-----------------------^
ÿþ是特殊字符(0xFE,0xFF)。 我不認為OP希望他們使用列名,如果是這樣,應將其括在下面
`ÿþName`
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