關於比較的 R switch 語句

Question

我正在嘗試編寫一個 R 腳本來根據在范圍內擬合一個值來評估不同的表達式。 這個想法是，如果 Length 在一個范圍內，它將以一種方式進行評估，如果它在更長的范圍內，它將以不同的方式進行評估。

我可以使用 if/else 語句來完成這項工作，但它非常難看，而且我確信必須有更好的方法......這是有效的代碼。

Length=8.2

if (Length<1) 
    mode="Walk"
else if (1<=Length & Length <5)
    mode="bike" 
else if (5<=Length & Length <10)
    mode="drive"
else if (Length>=10)
    mode="fly"

我一直在嘗試使用 switch 函數來做一些事情，但它似乎只適用於文本或整數......有沒有辦法讓 switch 語句在這樣的每種情況下進行評估？

Length=3.5

switch(Length,
       (Length<1)  mode="Walk"
       (1<=Length & Length <5)  mode="bike"
       (5<=Length & Length <10)  mode="drive"
       (Length=>10)  mode="fly"
)

Answer 1

這是與 Josh 類似的答案，但使用的是findInterval ：

Length <- 0:11

cuts <- c(-Inf, 1, 5, 10, Inf)
labs <- c("Walk", "bike", "drive", "fly")

labs[findInterval(Length, cuts)]
# [1] "Walk"  "bike"  "bike"  "bike"  "bike"  "drive" "drive"
# [8] "drive" "drive" "drive" "fly"   "fly"

您還可以使用嵌套的ifelse語句，這是一個品味問題：

ifelse(Length < 1,  "Walk",
ifelse(Length < 5,  "bike",
ifelse(Length < 10, "drive",
                    "fly")))
# [1] "Walk"  "bike"  "bike"  "bike"  "bike"  "drive" "drive"
# [8] "drive" "drive" "drive" "fly"   "fly"

Answer 2

使用 dplyr 的case_when語句：

library(dplyr)
Length <- 3.5
mode <- case_when(
                Length < 1 ~ "Walk",
                1 <= Length & Length < 5 ~ "bike",
                5 <= Length & Length < 10 ~ "drive",
                Length >= 10 ~ "fly"
          )
mode
#> [1] "bike"

Answer 3

cut()做你需要的嗎？

Length <- 0:11

cuts <- c(-Inf, 1, 5, 10, Inf)
labs <- c("Walk", "bike", "drive", "fly")

as.character(cut(Length, breaks = cuts, labels = labs, include.lowest=TRUE))
#  [1] "Walk"  "Walk"  "bike"  "bike"  "bike"  "bike"  "drive" "drive" "drive"
# [10] "drive" "drive" "fly"  

Answer 4

剪切和切換：使用來自 cut() 的因子級別並傳入 switch() 以返回適當的代碼。

 transport <- function(dist) {
   stopifnot(is.numeric(dist))
   x <- as.numeric(cut(dist, c(-Inf,0,1,5,10,Inf)), right = TRUE)
   switch (x,
           "No distance",
           "Walk",
           "Bike",
           "Drive",
           "Fly",
           stop("Not sure")
   )
 }

Answer 5

這個答案對於手頭的例子來說有點矯枉過正，但它非常靈活——你可以在evaluate_like_this()做任何事情。

evaluate_one <- function(x) {
  switch(
    x,
    evaluate_like_this(x, "Walk"),
    evaluate_like_this(x, "No distance"),
    evaluate_like_this(x, "Bike"),
    evaluate_like_this(x, "Drive"),
    evaluate_like_this(x, "Fly")
  )
}

evaluate_like_this <- function(x, y) {
  paste0(x, ": ", y)
}

these_data <- 0:11
intervals <- cut(these_data, breaks = c(-Inf, 1, 5, 10, Inf), label = FALSE)
unlist(lapply(intervals, evaluate_one))
#>  [1] "1: Walk"        "1: Walk"        "2: No distance" "2: No distance"
#>  [5] "2: No distance" "2: No distance" "3: Bike"        "3: Bike"       
#>  [9] "3: Bike"        "3: Bike"        "3: Bike"        "4: Drive"

^{由reprex 包(v0.2.1) 於2018年 12 月 19 日創建}

Answer 6

length <- 3.5
cuts <- c( 1, 5, 10, Inf )
labs <- c( "Walk", "bike", "drive", "fly" )
x <- which( cuts > length )[1]
switch(x,{labs[1]},{labs[2]},{labs[3]},{labs[4]})