[英]Error deleting image with AJAX and PHP using unlink
我正在嘗試使用AJAX和PHP從文件夾中刪除選定的圖像。 我沒有看到任何錯誤,請問您對我擁有的代碼有何看法? 提前致謝
AJAX代碼:
function createAjax()
{
var objAjax = false;
if (window.XMLHttpRequest)
{
objAjax = new XMLHttpRequest ();
}
else
{
if (window.ActiveXObject)
{
try
{
objAjax = new ActiveXObject ("Msxml2.XMLHTTP");
}
catch (e)
{
try
{
objAjax = new ActiveXObject ("Microsoft.XMLHTTP");
}
catch (e)
{
}
}
}
else
{
objAjax = false;
}
}
return objAjax;
}
function eliminar(id_foto)
{
var ajax = createAjax();
ajax.open("POST", "delete_img.php",true);
ajax.onreadystatechange=function()
{
if (ajax.readyState == 4)
{
//AQUI DEBES DE PONER EL CODIGO RESPECTIVO PARA ELIMINAR DEL NAVEGADOR
// EL DIV EN CUESTION o simplemente hacer su contenido vacio, que es lo que hare
document.getElementById("delete"+id_foto).innerHTML = "";
document.getElementById("div_mensajes").innerHTML
}
else
{
document.getElementById("div_mensajes").innerHTML = "<br><center>Eliminando<img src = 'images/ajax-loader.gif' /></center>";
}
}
ajax.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
ajax.send("id_foto="+id_foto);
}
首先顯示它的HTML和PHP代碼:
$handle = opendir(dirname(realpath(__FILE__)).'/uploads/');
while($file = readdir($handle)) {
if($file !== '.' && $file !== '..') {
if(file_exists('uploads/Thumbs.db')){
unlink('uploads/Thumbs.db');
}
echo'<div class="gallery-item" id="delete'.$file.'">
<p class="gallery-clean">
<a class="image" rel="'.$file.'" rev="'.$file.'" href="uploads/'.$file.'" title="">
<img src="uploads/'.$file.'" alt="'.$file.'"></a></p>
<div>
<a class="ico ico-delete" rel="9" rev="2" href="#" onclick = "eliminar_ajax('.$file.');"><span></span></a>
<a class="ico ico-edit" rel="9" href="#"><span></span></a>
<a class="ico ico-resize" rel="9" href="#"><span></span></a>
<a class="ico ico-full" rel="group" href="#"><span></span></a>
</div></div>';
}
}
PHP代碼刪除文件:
$dir = "uploads/";
$file = $_POST['id_foto'];
$img = $dir.$file;
unlink($img);
好! 我已經解決了使用此:
script type="text/javascript">
function deleteFile(fname,directory)
{
$.ajax({ url: "delete_img.php",
data: {"file":fname,"directory":directory},
type: 'post',
success: function(output) {
alert(output);
$("#delete"+file).remove();
}
});
}
</script>
如果我叫它怎么去掉div
#delete.'<?php echo $file?>
圖像的擴展名是什么? 像這樣將其添加到$file
$file .= ".whateverextensionithas";
更清楚一點
$dir = "uploads/";
$file = $_POST['id_foto'];
$file .= ".whateverextensionithas";
$img = $dir.$file;
unlink($img);
或者說清楚一點
$dir = "uploads/";
$ext = ".whateverextensionithas";
$file = $dir.$_POST['id_foto'].$ext;
if(file_exists($file))
unlink($file);
else
echo "file does not exist";
嘗試這段代碼:
if(isset($_POST['id_foto'])){
$dir = "uploads/";
$file = $_POST['id_foto'];
$img = $dir.$file;
$f = fopen($dir."post.txt", 'w+');
fwrite($f, $img);
fclose($f);
}
並檢查post.txt
以查看獲得的輸出類型。
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