與同一實體的一對多關系

Question

請在下面找到實體代碼，

@Entity
public class A implements Serializable {

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private Long id;

    @OneToMany(cascade={CascadeType.PERSIST, CascadeType.MERGE}, fetch = FetchType.LAZY, mappedBy="parentActivity")        
    private Set<A> subActivities;

    @ManyToOne(cascade = CascadeType.REFRESH, fetch = FetchType.LAZY)
    @JoinColumn(name = "PARENTACTIVITYID", insertable = true, updatable = true)
    private A parentActivity;

    // Getters, Setters, serialVersionUID, etc...
}   

如果我們想同時堅持父母和孩子，那么下面的代碼可以完美地運行

public static void main(String[] args) {

    EntityManager em = ... // from EntityManagerFactory, injection, etc.

    em.getTransaction().begin();

    A parentActivuty   = new A();
    A subActivity1      = new A();
    A subActivity2 = new A();

    son.setParentActivity(parent);
    daughter.setParentActivity(parent);
    parent.setSubActivity(Arrays.asList(subActivity1, subActivity2));

    em.persist(parent);
    em.persist(son);
    em.persist(daughter);

    em.getTransaction().commit();
}

但在這種情況下，我在數據庫中有父對象，並希望持久保存子對象可能的解決方案......？

Answer 1

您從數據庫中獲取父級，執行附件並保留兩個子級：

A parent = em.get(A.class, parentId);
A son = new A();
A daughter = new A();
son.setParentActivity(parent);
daughter.setParentActivity(parent);
em.persist(son);
em.persist(daughter);
parent.getSubActivities().add(son);
parent.getSubActivities().add(daughter);