沒有時區的Javascript日期格式

Question

我有一個從輸入值定義的javascript變量。

$d = $('#date').val();
$myDateParts = $d.split("-");
$dflip = new Date($myDateParts[2], ($myDateParts[1]-1), $myDateParts[0]);
console.log($dflip);

$dflip = Wed Sep 19 00:00:00 UTC+0100 2012 

如何將輸出格式化為：

Wed Sep 19

Answer 1

您可以使用substring或toDateString或同時使用兩者

例如：

var dateString = new Date(2012, 0, 31).toDateString();
var noYear = dateString.substring(0, dateString.length-5);
console.log(noYear);

Answer 2

嘗試以下代碼。

<script src="../../ui/jquery.ui.datepicker.js"></script>

$( "#datepicker" ).datepicker( "D M yy", dflip.val());

Answer 3

這可能不是完成所需內容的最干凈，最有效或最佳的方法，但是我創建了一個函數來返回不帶時區的日期。 您可以調整“ theDate”變量以僅返回所需日期的一部分。

    function properDate(){  

    var d = new Date();

    var DayOfMonth = d.getDate();
    var DayOfWeek = d.getDay();
    var Month = d.getMonth();
    var Year = d.getFullYear();
    var Hours = d.getHours();
    var Minutes = d.getMinutes();
    var Seconds = d.getSeconds();

    switch (DayOfWeek) {
    case 0:
        day = "Sun";
        break;
    case 1:
        day = "Mon";
        break;
    case 2:
        day = "Tue";
        break;
    case 3:
        day = "Wed";
        break;
    case 4:
        day = "Thu";
        break;
    case 5:
        day = "Fri";
        break;
    case 6:
        day = "Sat";
        break;
    }

    switch (Month) {
    case 0:
        month = "Jan";
        break;
    case 1:
        month = "Feb";
        break;
    case 2:
        month = "Mar";
        break;
    case 3:
        month = "Apr";
        break;
    case 4:
        month = "May";
        break;
    case 5:
        month = "Jun";
        break;
    case 6:
        month = "Jul";
        break;
    case 7:
        month = "Aug";
        break;
    case 8:
        month = "Sep";
        break;
    case 9:
        month = "Oct";
        break;
    case 10:
        month = "Nov";
        break;
    case 11:
        month = "Dec";
        break;
    }




    var theDate = day + " " + month + " " + DayOfMonth + "  " + Year + " " + Hours + ":" + Minutes + ":" + Seconds;

    return theDate; 
}

Answer 4

我的DateExtentions庫可以做到這一點-盡管如果您只是做一個簡單的格式，這可能會顯得有些矯kill過正。

http://depressedpress.com/javascript-extensions/dp_dateextensions/

我可以根據傳遞的掩碼來解析日期，並根據自己的喜好格式化輸出（它還會執行各種日期數學和實用程序操作，因此，它可能比您需要的還要重）。