JPA OneToMany雙向

Question

我知道有很多問題，但我無法找到解決問題的好方法。

我使用Jboss作為7，Spring和Hibernate（4）作為JPA 2.0提供程序，所以我有簡單的@OneToMany雙向關系：

我有這樣的超級人：

@MappedSuperclass
@Inheritance(strategy=InheritanceType.JOINED)
public abstract class Person {

@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Long id;

@NotNull
@Size(min = 1, max = 25)
@Pattern(regexp = "[A-Za-z ]*", message = "must contain only letters and spaces")
private String name;  


public Person(String name) {
    super();
    this.name = name;
}

和班級成員：

@Entity
@Table(uniqueConstraints = @UniqueConstraint(columnNames = "email"))
public class Member extends Person implements Serializable
{
   /** Default value included to remove warning. Remove or modify at will. **/
   private static final long serialVersionUID = 1L;


   @NotNull
   @NotEmpty
   @Email
   private String email;

   @NotNull
   @Size(min = 10, max = 12)
   @Digits(fraction = 0, integer = 12)
   @Column(name = "phone_number")
   private String phoneNumber;

   @OneToMany(cascade=CascadeType.ALL , mappedBy="member" , fetch=FetchType.EAGER)
   private List<Order> orders;

還有班級訂單：

@Entity
public class Order {

@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Integer id;

private float price; 

@ManyToOne(optional=false)
private Member member;

private String name;

所以我認為這是一個很好的配置，但我在內存中的HSQL測試這個應用程序，我有錯誤：

Hibernate: alter table Order drop constraint FK48E972E548C740B
2012-09-20 16:25:37 org.hibernate.tool.hbm2ddl.SchemaExport perform
ERROR: HHH000389: Unsuccessful: alter table Order drop constraint FK48E972E548C740B
2012-09-20 16:25:37 org.hibernate.tool.hbm2ddl.SchemaExport perform
ERROR: Blad skladniowy w wyrazeniu SQL "ALTER TABLE ORDER[*] DROP CONSTRAINT FK48E972E548C740B "; oczekiwano "identifier"
Syntax error in SQL statement "ALTER TABLE ORDER[*] DROP CONSTRAINT FK48E972E548C740B "; expected "identifier"; SQL statement:
alter table Order drop constraint FK48E972E548C740B [42001-165]

並且 ：

Syntax error in SQL statement "CREATE TABLE ORDER[*] (ID INTEGER GENERATED BY DEFAULT AS IDENTITY, NAME VARCHAR(255), PRICE FLOAT NOT NULL, MEMBER_ID BIGINT NOT NULL, PRIMARY KEY (ID)) "; expected "identifier"; SQL statement:

我的JUnit測試失敗了我不知道這個配置有什么問題......

這是我的簡單說法：

  @Test
public void testInsertWithOrder(){
    Order order = new Order(20.0f, "first stuff");
    Order order2 = new Order(40.0f, "secondary stuff");
    List<Order> orders = new ArrayList<Order>();
    orders.add(order2);
    orders.add(order);

    Member member = new Member("Member name", "member23@gmail.com", "2125552141", orders);

    memberDao.register(member);

    List<Member> members = memberDao.findAllOrderedByName();

    Assert.assertNotNull(members);
    Assert.assertEquals(1, members.size());     

}

Answer 1

將表名從“order”更改為不同的名稱，例如PersonOrder

Answer 2

在Order Class中的member中，缺少@JoinColumn注釋。 請嘗試以下方式。

@ManyToOne(optional=false)
@JoinColumn(name = "memberId", referencedColumnName = "id")
private Member member;

Answer 3

@CycDemo

我只是想出來，在我的構造中我現在有：

    @OneToMany(cascade=CascadeType.ALL , mappedBy="member" , fetch=FetchType.EAGER)
    private List<UOrder> orders = new ArrayList<UOrder>();



       public Member(String name, String email, String phoneNumber ,List<UOrder> orders) {
       super(name);
       this.orders = orders;
       this.email = email;
       for(UOrder o : orders){
           o.setMember(this);          
       }
       this.orders = orders;

   }

螞蟻這是我需要的:)））