php while循環只顯示跨多個表的mysql查詢的一個結果

Question

我遇到了一個只返回一個結果的while語句的問題。 這是我第一次嘗試從幾個表中顯示產品信息而我不知道我做錯了什么。 這是代碼：

<?php
    require('./includes/config.inc.php');
    require(MYSQL);

    $sql = sprintf("SELECT * FROM tea");

    $res = mysqli_query($dbc, $sql);

    if(!$res){
    die('Could not complete query: '.mysqli_error($dbc));
    } else {

    echo 'Success!<br />';

    while($row = mysqli_fetch_array($res)){
        $table = $row['category'];
        $inum = $row['item_number'];

        echo $table.' '.$inum.'<br />';

        $fetch = sprintf("SELECT sub_category, item_name, description FROM $table WHERE item_number ='$inum'");
        $fetchRes = mysqli_query($dbc, $fetch);

        if(!$fetchRes){
            die('Could not fetch: '.mysqli_error($dbc));
        } else {
            while($fetchRow = mysqli_fetch_array($fetchRes)){
                $subCat = $fetchRes['sub_category'];
                $iNumber = $inum;
                $iname = $fetchRes['item_name'];
                $desc = $fetchRes['description'];

                echo $id.' '.$subCat.' '.$iNumber.' '.$iname.' '.$desc.'<br />';
            }
        }
    }
}

Answer 1

在while循環中，您應該使用$fetchRow變量作為從中獲取列的數組，例如'sub_category'。

Answer 2

IS

  $subCat = $fetchRes['sub_category'];
  $iNumber = $inum;
  $iname = $fetchRes['item_name'];
  $desc = $fetchRes['description'];

需要：Res to Row

 $subCat = $fetchRow['sub_category'];
 $iNumber = $inum;
 $iname = $fetchRow['item_name'];
 $desc = $fetchRow['description'];