帶有復雜ORDER BY的MySQL查詢

Question

我有以下查詢：

SELECT id, title, adcontent, adtargetURL, locationpage, 
locationarg, locationid, displayorder, visible, schedstart, 
schedstop, created, modified, createdby, modifiedby
FROM ads            
ORDER BY locationpage, locationarg, locationid, title 

我需要按以下方式訂購字段：

• 按位置排序，首先選擇值為'all'的任何字段，然后按升序排序
• 然后通過locationarg首先使用任何NULL或空字符串值，然后在asc中使用其余值
• 然后通過locationid首先使用任何NULL或0值，其余部分在asc中
• 在那些之內，首先按'1'的顯示順序排序，然后是NULL，然后是'2'
• 最后，如果其中任何一個都是相同的，則通過ASC中的標題

我的ORDER BY應該如何實現這一目標？

這是我到目前為止:(從下面更新）

ORDER BY locationpage='all', 
         locationpage ASC, 
         locationarg ASC, 
         locationid ASC, 
         displayorder='1', 
         ISNULL(displayorder), 
         displayorder='2', 
         title ASC

......但這不起作用！

Answer 1

您最好的選擇是使用一個計算字段，根據您的規則生成訂單ID ..我稍后會添加一個示例..

select
case
  when locationpage = "all" then 10
  when ISNULL(locationarg)  then 20
  ....
  else 50 
end as OrderID,
id, 
title, 
....

FROM ads            

ORDER BY OrderID DSEC

Answer 2

給這個打擊：

select id, title, adcontent, adtargetURL, locationpage, locationarg, locationid, displayorder, visible, schedstart, schedstop, created, modified, createdby, modifiedby 
from ads
order by case when locationpage='all' then 0 else 1 end, 
         locationpage, 
         case when locationarg is null or locationarg='' then 0 else 1 end,
         locationarg ASC, 
         case when locationid is null OR locationid='0' then 0 else 1 end, 
         locationid, 
         case when displayorder =1 then 0 when displayorder is null then 1 when displayorder = 2 then 2 else 3 end,
         title;