[英]Split a String based on regex
我有一個字符串需要根據“,”(逗號)的出現進行拆分,但需要忽略一對括號中出現的任何字符串。 例如, B2B,(A2C,AMM),(BNC,1NF),(106,A01),AAA,AX3
應該分成
B2B,
(A2C,AMM),
(BNC,1NF),
(106,A01),
AAA,
AX3
對於沒有巢
,(?![^\(]*\))
FOR NESTED (括號內的括號)
(?<!\([^\)]*),(?![^\(]*\))
試試以下:
var str = 'B2B,(A2C,AMM),(BNC,1NF),(106,A01),AAA,AX3';
console.log(str.match(/\([^)]*\)|[A-Z\d]+/g));
// gives you ["B2B", "(A2C,AMM)", "(BNC,1NF)", "(106,A01)", "AAA", "AX3"]
Java版:
String str = "B2B,(A2C,AMM),(BNC,1NF),(106,A01),AAA,AX3";
Pattern p = Pattern.compile("\\([^)]*\\)|[A-Z\\d]+");
Matcher m = p.matcher(str);
List<String> matches = new ArrayList<String>();
while(m.find()){
matches.add(m.group());
}
for (String val : matches) {
System.out.println(val);
}
一個簡單的迭代可能比任何正則表達式都更好,特別是如果你的數據在括號內有括號。 例如:
String data="Some,(data,(that),needs),to (be, splited) by, comma";
StringBuilder buffer=new StringBuilder();
int parenthesesCounter=0;
for (char c:data.toCharArray()){
if (c=='(') parenthesesCounter++;
if (c==')') parenthesesCounter--;
if (c==',' && parenthesesCounter==0){
//lets do something with this token inside buffer
System.out.println(buffer);
//now we need to clear buffer
buffer.delete(0, buffer.length());
}
else
buffer.append(c);
}
//lets not forget about part after last comma
System.out.println(buffer);
產量
Some
(data,(that),needs)
to (be, splited) by
comma
試試這個
\w{3}(?=,)|(?<=,)\(\w{3},\w{3}\)(?=,)|(?<=,)\w{3}
說明:有三個部分用OR (|)
分隔
\\w{3}(?=,)
- 匹配3個任何字母數字字符(包括下划線),並為逗號做好積極展望
(?<=,)\\(\\w{3},\\w{3}\\)(?=,)
- 匹配這種模式(ABC,E4R)
,並做一個積極的前瞻,並留意逗號
(?<=,)\\w{3}
- 匹配3個任何字母數字字符(包括下划線)並為逗號做正面看法
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