[英]Java Stack Sort Symbol Balancing
我寫的程序必須讀取一個加載的文本文檔並檢查是否所有(,[,和{是平衡的以及忽略“之間的任何內容”和之后//。我到目前為止檢查是否前三個符號都是平衡的,但是我在檢查第一次出現的行號時遇到了麻煩。我知道如果下一個符號是“或//,我忽略該行或直到我點擊了下一個“,但我不確定正確的語法。任何幫助都會受到贊賞。這是我到目前為止所擁有的:
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.util.*;
import java.io.*;
import javax.swing.filechooser.*;
import javax.swing.text.BadLocationException;
public class Sorting extends JFrame implements ActionListener{
private Stack<Character> symbolStack;
JTextArea opentextArea;
JTextArea placetextArea;
JMenuItem open;
final JFileChooser fc = new JFileChooser();
public static void main(String [] args)
{
Sorting gui = new Sorting();
}
public Sorting()
{
JFrame frame = new JFrame();
setLayout(new GridLayout(1,2));
setTitle("Stack Sort");
JMenuBar menuBar = new JMenuBar();
JMenu menuItems = new JMenu("File");
open = new JMenuItem("Open");
open.addActionListener(this);
JMenuItem reset = new JMenuItem("Reset");
reset.addActionListener(
new ActionListener(){
public void actionPerformed(ActionEvent e)
{
opentextArea.setText("");
placetextArea.setText("");
}
}
);
menuItems.add(open);
menuItems.add(reset);
menuBar.add(menuItems);
setJMenuBar(menuBar);
opentextArea = new JTextArea();
placetextArea = new JTextArea();
add(opentextArea);
add(placetextArea);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
pack();
setVisible(true);
}
public void actionPerformed(ActionEvent event)
{
int returnVal = fc.showOpenDialog(this);
if (returnVal == JFileChooser.APPROVE_OPTION)
{
File file = fc.getSelectedFile();
FileInputStream is = null;
try
{
is = new FileInputStream(file);
}
catch (FileNotFoundException e)
{
System.out.println("Exception: " + e.toString());
}
byte [] nextChar = new byte[2];
try
{
int value = is.read(nextChar);
int num = 1;
opentextArea.append(num + ":" );
while (value != -1)
{
String newString = new String(nextChar);
if (nextChar[0] == '\n' || nextChar[0] == '\r')
{
num++;
opentextArea.append(newString + num + ":" );
}
else
opentextArea.append(newString);
value = is.read(nextChar);
}
}
catch (IOException e)
{
System.out.println("Exception: " + e.toString());
}
Stack<Character> stack = new Stack<Character>();
String s = opentextArea.getText();
int index = 0;
int numline = 1;
while(index < s.length()) {
char ch = s.charAt(index);
if (ch == '\n' || ch == '\r')
{
numline++;
index++;
}
else
if(ch == '{' || ch == '[' || ch == '(')
{
stack.push(ch);
index++;
}
else {
if(stack.empty())
{
index++;
//placetextArea.append("No balance characters found.");
continue;
}
char ch1 = stack.pop();
if(ch1 == '{' && ch == '}' || ch1 == '[' && ch == ']' || ch1 == '(' && ch == ')')
{
placetextArea.append(ch1 + " at line " +numline + " matches up with " + ch + " at line " + numline + "\n");
}
else
if(ch1 == '{' && ch != '}' || ch1 == '[' && ch != ']' || ch1 == '(' && ch != ')')
{
placetextArea.append("error unmatched " + ch1 + "at line " +numline);
break;
}
}
}
}
}
}
這是我編輯的代碼:
Stack<Character> stack = new Stack<Character>();
String s = opentextArea.getText();
int index = 0;
int numline = 1;
while(index < s.length()) {
char ch = s.charAt(index);
if (ch == '\n' || ch == '\r')
{
numline++;
index++;
}
else
if(ch == '{' || ch == '[' || ch == '(')
{
stack.push(ch);
index++;
}
else {
if(stack.empty())
{
index++;
//placetextArea.append("No balance characters found.");
continue;
}
// pop an item from stack
if(ch == '}' || ch == ']' || ch == ')')
{
char ch1 = stack.pop();
// check if it's a matching pair
if(ch1 == '{' && ch == '}' || ch1 == '[' && ch == ']' || ch1 == '(' && ch == ')')
{
placetextArea.append(ch1 + " at line " +numline + " matches up with " + ch + " at line " + numline + "\n");
}
else
if(ch1 == '{' && ch != '}' || ch1 == '[' && ch != ']' || ch1 == '(' && ch != ')')
{
placetextArea.append("error unmatched " + ch1 + "at line " +numline);
break;
}
}
}
}
只有在遇到)
, }
或]
之一時才需要從堆棧中彈出。 然后檢查關閉的一個是否與開頭匹配。 此外,您還需要在不匹配時定義行為:向后推開口或放下它。 在EOF,你應該檢查堆棧是否為空。 否則你會有不平衡的東西。
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