[英]How to set message when I get Exception
public class XMLParser {
// constructor
public XMLParser() {
}
public String getXmlFromUrl(String url) {
String responseBody = null;
getset d1 = new getset();
String d = d1.getData(); // text
String y = d1.getYear(); // year
String c = d1.getCircular();
String p = d1.getPage();
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("YearID", y));
nameValuePairs.add(new BasicNameValuePair("CircularNo", c));
nameValuePairs.add(new BasicNameValuePair("SearchText", d));
nameValuePairs.add(new BasicNameValuePair("pagenumber", p));
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
responseBody = EntityUtils.toString(entity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
// return XML
return responseBody;
}
public Document getDomElement(String xml) {
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (SAXException e) {
Log.e("Error: ", e.getMessage());
// i m getting Exception here
return null;
} catch (IOException e) {
Log.e("Error: ", e.getMessage());
return null;
}
return doc;
}
/**
* Getting node value
*
* @param elem
* element
*/
public final String getElementValue(Node elem) {
Node child;
if (elem != null) {
if (elem.hasChildNodes()) {
for (child = elem.getFirstChild(); child != null; child = child
.getNextSibling()) {
if (child.getNodeType() == Node.TEXT_NODE) {
return child.getNodeValue();
}
}
}
}
return "";
}
/**
* Getting node value
*
* @param Element
* node
* @param key
* string
* */
public String getValue(Element item, String str) {
NodeList n = item.getElementsByTagName(str);
return this.getElementValue(n.item(0));
}
}
我在此類中獲取數據解析異常。 我想在從Activity擴展的另一個類中打印此消息。 你能告訴我如何嗎? 我嘗試了很多,但沒能做。
public class AndroidXMLParsingActivity extends Activity {
public int currentPage = 1;
public ListView lisView1;
static final String KEY_ITEM = "docdetails";
static final String KEY_NAME = "heading";
public Button btnNext;
public Button btnPre;
public static String url = "http://dev.taxmann.com/TaxmannService/TaxmannService.asmx/GetNotificationList";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// listView1
lisView1 = (ListView) findViewById(R.id.listView1);
// Next
btnNext = (Button) findViewById(R.id.btnNext);
// Perform action on click
btnNext.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
currentPage = currentPage + 1;
ShowData();
}
});
// Previous
btnPre = (Button) findViewById(R.id.btnPre);
// Perform action on click
btnPre.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
currentPage = currentPage - 1;
ShowData();
}
});
ShowData();
}
public void ShowData() {
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(url); // getting XML
Document doc = parser.getDomElement(xml); // getting DOM element
NodeList nl = doc.getElementsByTagName(KEY_ITEM);
int displayPerPage = 5; // Per Page
int TotalRows = nl.getLength();
int indexRowStart = ((displayPerPage * currentPage) - displayPerPage);
int TotalPage = 0;
if (TotalRows <= displayPerPage) {
TotalPage = 1;
} else if ((TotalRows % displayPerPage) == 0) {
TotalPage = (TotalRows / displayPerPage);
} else {
TotalPage = (TotalRows / displayPerPage) + 1; // 7
TotalPage = (int) TotalPage; // 7
}
int indexRowEnd = displayPerPage * currentPage; // 5
if (indexRowEnd > TotalRows) {
indexRowEnd = TotalRows;
}
// Disabled Button Next
if (currentPage >= TotalPage) {
btnNext.setEnabled(false);
} else {
btnNext.setEnabled(true);
}
// Disabled Button Previos
if (currentPage <= 1) {
btnPre.setEnabled(false);
} else {
btnPre.setEnabled(true);
}
// Load Data from Index
int RowID = 1;
ArrayList<HashMap<String, String>> menuItems = new ArrayList<HashMap<String, String>>();
HashMap<String, String> map;
// RowID
if (currentPage > 1) {
RowID = (displayPerPage * (currentPage - 1)) + 1;
}
for (int i = indexRowStart; i < indexRowEnd; i++) {
Element e = (Element) nl.item(i);
// adding each child node to HashMap key => value
map = new HashMap<String, String>();
map.put("RowID", String.valueOf(RowID));
map.put(KEY_NAME, parser.getValue(e, KEY_NAME));
// adding HashList to ArrayList
menuItems.add(map);
RowID = RowID + 1;
}
SimpleAdapter sAdap;
sAdap = new SimpleAdapter(AndroidXMLParsingActivity.this, menuItems,
R.layout.list_item, new String[] { "RowID", KEY_NAME },
new int[] { R.id.ColRowID, R.id.ColName });
lisView1.setAdapter(sAdap);
}
}
這是我想在其中打印消息的班級
您可以像下面這樣簡單地用Try/Catch
塊包圍代碼:
String xml;
Document doc;
NodeList nl;
try {
xml = parser.getXmlFromUrl(url); // getting XML
doc = parser.getDomElement(xml); // getting DOM element
nl = doc.getElementsByTagName(KEY_ITEM);
} catch (Exception e) {
Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_LONG).show();
}
這樣,您不必在XMLParser
類中進行任何更改,並且可以輕松處理在主類本身中解析代碼時發生的任何異常。 而且,對於顯示錯誤消息,對我來說, Toast
是最好的選擇。
希望這會有所幫助..謝謝。
我會說,在XMLParser.getDomElement()
方法中添加throws SAXException
,並且在此方法中不要捕獲SAXException
為:
public Document getDomElement(String xml) throws SAXException {
在要調用getDomElement()
方法的AndroidXMLParsingActivity.ShowData()
中捕獲SAXException
並以所需方式打印消息,例如
public void ShowData() {
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(url); // getting XML
Document doc = null;
try{
doc = parser.getDomElement(xml); // getting DOM element
}catch(SAXException sae){
//print the desired message here
}
.......
.......
}
只需將構造函數傳遞給XMLParser
類,然后將其用作構造函數即可。 或者,您可以嘗試使用getApplicationContext()
,當遇到如下所示的異常時,可以簡單地顯示Toast
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
Log.e("Error: ", e.getMessage());
Toast.makeToast(con, e.toString(), Toast.Long).show(); // Will show the message of exception
return null;
} catch (SAXException e) {
Log.e("Error: ", e.getMessage());
Toast.makeToast(con, e.toString(), Toast.Long).show(); // Will show the message of exception
// i m getting Exception here
return null;
} catch (IOException e) {
Log.e("Error: ", e.getMessage());
Toast.makeToast(con, e.toString(), Toast.Long).show(); // Will show the message of exception
return null;
}
更新資料
好的,只需按照下面的方法傳遞構造函數-在調用XMLparser
類的地方,就像下面這樣調用-
....
XMLParser xml = new XMLParser(AndroidXMLParsingActivity.this);
....
而且,在XMLParser
類中,您可以像下面這樣提及您的構造函數-
public class XMLParser {
Context con;
public XMLParser(Context context) {
con = context;
}
......
}
並且,將此con
用作XMLParser
類中的構造函數。
為了顯示來自非活動類的消息,您需要將“當前活動上下文”傳遞為:
public class XMLParser {
Context context
// constructor
public XMLParser(Context conts) {
context =conts;
}
///YOUR CODE
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
Log.e("Error: ", e.getMessage());
Toast.makeToast(context, e.toString(), Toast.Long).show();
return null;
} catch (SAXException e) {
Log.e("Error: ", e.getMessage());
Toast.makeToast(context, e.toString(), Toast.Long).show();
// i m getting Exception here
return null;
} catch (IOException e) {
Log.e("Error: ", e.getMessage());
Toast.makeToast(context, e.toString(), Toast.Long).show();
return null;
}
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