如何從鍵將Ruby數組排序為哈希？

Question

我有一個Ruby數組，看起來像：

[
     #<Share _id: 507fd5a8ab432a6a35000006, _type: nil, price: {"cents"=>25535, "currency_iso"=>"USD"}, company_id: "507fcdb8ab432ac733000001", user_id: "507fcb06ab432a7c2e000001">,
     #<Share _id: 507fd5a8ab432a6a35000007, _type: nil, price: {"cents"=>25535, "currency_iso"=>"USD"}, company_id: "507fcdb8ab432ac733000001", user_id: "507fcb06ab432a7c2e000002">
] 

我如何通過關鍵的company.symbol （這是一個Mongoid關系，並存在於每個Share對象中）對它進行排序，所以它最終變成了像

{
    :appl => [#<Share _id: 507fd5a8ab432a6a35000006, _type: nil, price: {"cents"=>25535, "currency_iso"=>"USD"}, company_id: "507fcdb8ab432ac733000001", user_id: "507fcb06ab432a7c2e000001">]
    :msft => [#<Share _id: 507fd5a8ab432a6a35000007, _type: nil, price: {"cents"=>25535, "currency_iso"=>"USD"}, company_id: "507fcdb8ab432ac733000001", user_id: "507fcb06ab432a7c2e000002">]
}

其中aapl和msft是在Share的company.symbol上可用的公司符號。 這可能嗎？

Answer 1

並非完全符合我的要求，但可以按我的意願工作：

@companies = current_user.shares.map { |s| s.company }.uniq.each do |company|
    puts "#{company.name}: #{company.shares.map { |s| s if s.user == current_user and s.company == company }}"
    # this prints all the shares of every company
end

Answer 2

hash = {}
shares.each{ |share|
  hash[share.company.symbol] = [] unless hash[share.company.symbol]
  hash[share.company.symbol] << share
}