PHP-MYSQL不能插入多行

Question

我在html的所有安裝程序和工作程序中都具有我的注冊表單，它可以運行並在第一次插入行到mysql表中，但是我無法再插入任何行。

我的PHP是：-

include "config.php";

$gamerid = $_POST['gamerid_create'];
$email = $_POST['email_create'];
$password = md5($_POST['password_create']);
$country = $_POST ['country_create'];

echo "<pre>";
print_r($_POST);
echo "</pre>";

$insert = "insert into users (gamerid,email,password,country) values('$gamerid','$email','$password','$country')";
mysql_query($insert);

現在，當我在mysql中創建表時，我使用了以下代碼：-

CREATE TABLE users
(
id INT primary key NOT NULL AUTO_INCREMENT,
gamerid varchar (255) NOT NULL,
email varchar (255) NOT NULL,
password varchar (255) NOT NULL,
country varchar (255) NOT NULL
)

為什么不插入更多行？

我的HTML如下：

<form id = "signup_form" method = "POST" action = "http://localhost:8080/quizicle/pages/register.php">
<table id = "signup_form_table" border = "0" class = "signup_table_body">
<tr class = "signup_form_tr_label">
<td class = "signup_form_td"><label for "gamerid" class = "signup_form_label">Create a Gamer ID:</label></td>
<td class = "signup_form_td"><label for "email" class = "signup_form_label">Your Email:</label></td>
<td class = "signup_form_td"><label for "password" class = "signup_form_label">Password:</label></td>
<td class = "signup_form_td"><label for "country" class = "signup_form_label">Country:</label></td>
<td class = "signup_form_td"></td>
</tr>

<tr class = "signup_form_tr">
<td class = "signup_form_td"><input type = "text" name = "gamerid_create" id = "gamerid_create" maxlength="50" class = "signup_form_input"/></td>
<td class = "signup_form_td"><input type = "text" name = "email_create" id = "email_create" maxlength="50" class = "signup_form_input"/></td>
<td class = "signup_form_td"><input type = "password" name = "password_create" id = "password_create" maxlength="50" class = "signup_form_input"/></td>
<td class = "signup_form_td">
<select name = "country_create">                                    <option>Please select a country</option> 
<option>United Kingdom</option> 
</select>
</td>
<td class = "signup_form_td"><input type = "submit" value = "Sign me up!" id = "btn_register" value = "register" class = "signup_form_submit_btn"/></td>
</tr>   
</table>
</form>

Answer 1

    <?php

include "config.php";

// INPUT CLEANING FUNCTION
function clean($str)
{
    $cleaned = mysql_real_escape_string(strip_tags($str));
    return $cleaned;
}

$gamerid = clean($_POST['gamerid_create']);
$email = clean($_POST['email_create']);
$password = clean(md5($_POST['password_create']));
$country = clean($_POST ['country_create']);


$insert = "insert into users(gamerid,email,password,country) values('$gamerid' ,'$email',' $password', '$country')";                        
mysql_query($insert);
?>

1. 檢查您的id字段是否自動遞增
2. 檢查輸入標簽或文本標簽的屬性名稱//可選建議
3. 使用使用PHP內置的filter_var函數驗證電子郵件
4. 驗證密碼的長度和強度
5. 還考慮一些命名約定
6. 使用框架CODEIGNITER或LARAVEL

Answer 2

這可能與您的主鍵id

讓我們更改sql，看看它是否有效。

$insert = "INSERT INTO users (id, gamerid, email, password, country) 
  VALUES (NULL, '{$_POST['gamerid_create']}', '{$_POST['email_create']}', 
  '{$_POST['password_create']}', '{$_POST['country_create']}');";

在使用PHP / MySQL開發技能時應考慮的一些事項：

• 驗證並整理您的用戶輸入。 SQL注入風險。 參見：mysql_real_escape_string（），此處有基本幫助。

• 您應該配置表，確保將字段類型和大小設置為所需的最小值，如果不全部填充，VARCHAR（255）將浪費大量空間。

• 始終至少使用md5算法對密碼進行哈希處理。