在多方面，SQL一對多匹配ALL的一方

Question

在以下一對多

CREATE TABLE source(id int, name varchar(10), PRIMARY KEY(id));
CREATE TABLE params(id int, source int, value int);

其中params.source是source.id的外鍵

INSERT INTO source values(1, 'yes');
INSERT INTO source values(2, 'no');

INSERT INTO params VALUES(1,1,1);
INSERT INTO params VALUES(2,1,2);
INSERT INTO params VALUES(3,1,3);

INSERT INTO params VALUES(4,2,1);
INSERT INTO params VALUES(5,2,3);
INSERT INTO params VALUES(6,2,4);

如果我有一個參數值列表（比如[1,2,3]），我如何在SQL中找到列表中所有值（源1，“是”）的所有源？

謝謝

Answer 1

SELECT s.*
FROM source AS s
 JOIN params AS p ON (p.source = s.id)
WHERE p.value IN (1,2,3)
GROUP BY s.id
HAVING COUNT(DISTINCT p.value) = 3;

您需要DISTINCT，因為不會阻止params.value重復。

Answer 2

編輯修改以處理給定源可能存在多個值的情況。

試試這個：

SELECT
    *
FROM
    source
WHERE
    (
        SELECT COUNT(DISTINCT value)
        FROM params
        WHERE params.source = source.id
          AND params.value IN (1, 2, 3)
    ) = 3

您也可以將其重寫為GROUP BY：

SELECT
    source.*
FROM
    source
    INNER JOIN params ON params.source = source.id
WHERE
    params.value IN (1, 2, 3)
GROUP BY
    source.id,
    source.name
HAVING
    COUNT(DISTINCT params.value) = 3