在文本文件中查找特定單詞並對其進行計數

Question

有人可以幫我代碼嗎？ 如何在文本文件中搜索任何單詞並計算重復的數量？

例如test.txt：

hi
hola
hey
hi
bye
hoola
hi

如果我想知道在test.txt中重復多少次“Hi”程序必須說“3次重復”

我希望你理解我想要的東西，謝謝你的答案。

Answer 1

public int countWord(String word, File file) {
int count = 0;
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
    String nextToken = scanner.next();
    if (nextToken.equalsIgnoreCase(word))
    count++;
}
return count;
}

Answer 2

HashMap h=new HashMap();                        
FileInputStream fin=new FileInputStream("d:\\file.txt");
BufferedReader br=new BufferedReader(new InputStreamReader(fin));
String n;
while((n=br.readLine())!=null)
{
    if(h.containsKey(n))
    {
    int i=(Integer)h.get(n);
    h.put(n,(i+1));
    }
    else
    h.put(n, 1);
}

現在遍歷此地圖以使用每個單詞作為地圖值的關鍵字來獲取每個單詞的計數

Answer 3

使用google guava庫中的 MultiSet集合。

Multiset<String> wordsMultiset = HashMultiset.create();
Scanner scanner = new Scanner(fileName);
while (scanner.hasNextLine()) {
    wordsMultiset.add(scanner.nextLine());
}
for(Multiset.Entry<String> entry : wordsMultiset ){
     System.out.println("Word : "+entry.getElement()+" count -> "+entry.getCount());
}

Answer 4

Apache Commons - StringUtils.countMatches（）

Answer 5

package File1;

import java.io.BufferedReader;
import java.io.FileReader;

public class CountLineWordsDuplicateWords {

public static void main(String[] args) {
    FileReader fr = null;
    BufferedReader br =null;

    String [] stringArray;
    int counLine = 0;
    int arrayLength ;
    String s="";
    String stringLine="";
    try{
        fr = new FileReader("F:/Line.txt");
        br = new BufferedReader(fr);
        while((s = br.readLine()) != null){
            stringLine = stringLine + s;
            stringLine = stringLine + " ";/*Add space*/
            counLine ++;
        }
        System.out.println(stringLine);

        stringArray = stringLine.split(" ");
        arrayLength = stringArray.length;
                     System.out.println("The number of Words is "+arrayLength);
        /*Duplicate String count code */
        for (int i = 0; i < arrayLength; i++) {
            int c = 1 ;
            for (int j = i+1; j < arrayLength; j++) {
                if(stringArray[i].equalsIgnoreCase(stringArray[j])){
                    c++;
                    for (int j2 = j; j2 < arrayLength; j2++) {
                        stringArray[j2] = stringArray[j2+1];
                        arrayLength = arrayLength - 1;
                    }

                }//End of If block
            }//End of Inner for block
        System.out.println("The "+stringArray[i]+" present "+c+" times .");
        }//End of Outer for block
        System.out.println("The number of Line is "+counLine);
        System.out.println();
        fr.close();
        br.close();
    }catch (Exception e) {
        e.printStackTrace();
    }
}//End of main() method 
}//End of class CountLineWordsDuplicateWords

Answer 6

package somePackage;   
public static void main(String[] args) {

            String path = ""; //ADD YOUR PATH HERE
            String fileName = "test2.txt";
            String testWord = "Macbeth"; //CHANGE THIS IF YOU WANT
            int tLen = testWord.length();
            int wordCntr = 0;
            String file = path + fileName;
            boolean check;

            try{
                FileInputStream fstream = new FileInputStream(file);
                BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
                String strLine;        
                //Read File Line By Line
                while((strLine = br.readLine()) != null){                
                    //check to see whether testWord occurs at least once in the line of text
                    check = strLine.toLowerCase().contains(testWord.toLowerCase());
                    if(check){                    
                        //get the line, and parse its words into a String array
                        String[] lineWords = strLine.split("\\s+");                    
                        for(String w : lineWords){
                            //first see if the word is as least as long as the testWord
                            if(w.length() >= tLen){
                                /*
                                1) grab the specific word, minus whitespace
                                2) check to see whether the first part of it having same length
                                    as testWord is equivalent to testWord, ignoring case
                                */
                                String word = w.substring(0,tLen).trim();                                                        
                                if(word.equalsIgnoreCase(testWord)){                                
                                    wordCntr++;
                                }                            
                            }
                        }                    
                    }   
                }            
                System.out.println("total is: " + wordCntr);
            //Close the input stream
            br.close();
            } catch(Exception e){
                e.printStackTrace();
            }
        }

Answer 7

public class Wordcount 
{
   public static void main(String[] args)
   {       
       int count=0;

       String str="hi this is is is line";

       String []s1=str.split(" ");

       for(int i=0;i<=s1.length-1;i++)
       {
          if(s1[i].equals("is"))
           {
               count++; 
           }
       }

       System.out.println(count);
   }
}

Answer 8

您可以逐行閱讀文本文件。 我假設每行可以包含多個單詞。 對於每一行，您可以致電：

String[] words = line.split(" "); 
for(int i=0; i<words.length; i++){
   if(words[i].equalsIgnoreCase(searhedWord))
         count++;
}

Answer 9

嘗試使用java.util.Scanner。

public int countWords(String w, String fileName) {
int count = 0;
Scanner scanner = new Scanner(inputFile);
scanner.useDelimiter("[^a-zA-Z]"); // non alphabets act as delimeters
String word = scanner.next();
if (word.equalsIgnoreCase(w))
    count++;
   return count;
}

Answer 10

使用Pattern和Matcher以這種方式嘗試。

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Dem {

    public static void main(String[] args){

        try {
            File f = new File("d://My.txt");
            FileReader fr = new FileReader(f);
            BufferedReader br = new BufferedReader(fr);
            String s = new String();

            while((s=br.readLine())!=null){

                s = s + s;

            }

            int count = 0;
            Pattern pat = Pattern.compile("it*");
            Matcher mat = pat.matcher(s);

            while(mat.find()){

                  if(mat.find()){

                      mat.start();
                      count++;

                  }

            }

            System.out.println(count);
        } catch (Exception e) {

            e.printStackTrace();
        }
    }

}

Answer 11

import java.io.*;
import java.util.*;

class filedemo
{
public static void main(String ar[])throws Exception
BufferedReader br=new BufferedReader(new FileReader("c:/file.txt"));
 System.out.println("enter the string which you search");
 Scanner ob=new Scanner(System.in);
 String str=ob.next();
 String str1="",str2="";
 int count=0;
while((str1=br.readLine())!=null)
 {
 str2 +=str1;

}  

 int index = str2.indexOf(str);

 while (index != -1) {
 count++;
 str2 = str2.substring(index + 1);
 index = str2.indexOf(str);
}

System.out.println("Number of the occures="+count);
}
}  

Answer 12

package com.test;

import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.util.Scanner;

public  class Test {

    public static void main(String[] args)  throws Exception{

        BufferedReader bf= new BufferedReader(new FileReader("src/test.txt"));
        Scanner sc = new Scanner(System.in);
        String W=sc.next();
        //String regex ="[\\w"+W+"]";
        int count=0;

        //Pattern p = Pattern.compile();
        String line=bf.readLine();
        String s[];
        do
        {
            s=line.split(" ");
            for(String a:s)
            {
                if(a.contains(W))
                    count++;

            }


            line=bf.readLine();


        }while(line!=null);
        System.out.println(count);
    }



}

Answer 13

public int occurrencesOfHi()
{
    String newText = Text.replace("Hi","");
    return (Text.length() - newText.length())/2;
}