[英]mysql_query() expects parameter 2 to be resource, boolean
我正在嘗試從數據庫中獲取數據,但是遇到此錯誤。 查詢中沒有錯誤,因為它可以在mysql中完美運行。
為什么我會收到此錯誤?
[client 127.0.0.1] PHP Warning: mysql_query() expects parameter 2 to be resource, boolean given in /var/www/imdb.php on line 35
[client 127.0.0.1] PHP Warning: mysql_error() expects parameter 1 to be resource, boolean given in /var/www/imdb.php on line 35
php代碼:
function getdirector($director)
{
global $db;
$query = 'select name from peopledb where peopleid = '.$director;
$result = mysql_query($query,$db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $name;
}
function getactor($actor)
{
$query = 'select name from peopledb where peopleid = '.$actor;
$result = mysql_query($query,$db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $name;
}
function getmovietype($type)
{
$query = 'select movietype from movietype where movieid = '.$type;
$result = mysql_query($query,$db) or die(mysql_error($db));
$row = mysql_fetch_assoc($result);
extract($row);
return $movietype;
}
$db = mysql_connect('localhost','root','saw123') or die("Connection error");
$db = mysql_select_db("moviesite",$db) or die(myql_error($db));
$query = 'select moviename,releaseyear,director,actor,type from movie';
$result = mysql_query($query,$db) or die(mysql_error($db));
$table = <<<ENDHTML
<div style="text-align: center;" >
<h2>The Ultimate movie database</h2>
<table border='1' cellpadding='1' cellspacing='2'
style="width: 70%; margin-left: auto; margin-right: auto;">
<tr>
<th>Movie title</th>
<th>year of release </th>
<th>Movie director</th>
<th>Movie Actor</th>
<th>Movie type</th>
</tr>
ENDHTML;
while ($row = mysql_fetch_assoc($result))
{
extract($row);
$director1 = getdirector($director);
$actor1 = getactor($actor);
$movietype1 = getmovietype($type);
$table .= <<<ENDHTML
<tr>
<td>$moviename</td>
<td>$releaseyear</td>
<td>$director1</td>
<td>$actor1</td>
<td>$movietype1</td>
</tr>
ENDHTML;
}
$table .=<<<ENDHTML
</table>
</div>
ENDHTML;
echo $table;
?>
* UPDATE :::無論我在哪里使用mysql_error()函數,它都顯示錯誤。 現在,刪除所有“ $ db”參數后,它就可以工作了。 為什么?*
只是這樣稱呼它:
$result = mysql_query($query);
如果您查看mysql_connect函數,它會在失敗時返回false(一個布爾值):
http://php.net/manual/zh/function.mysql-connect.php
因此,您的連接可能甚至無法建立。
編輯:看一下這個函數: http : //php.net/manual/en/function.mysql-select-db.php
您正在致電:
$db = mysql_connect('localhost','root','saw123') or die("Connection error");
$db = mysql_select_db("moviesite",$db) or die(myql_error($db));
第二行將$ db設置為true或false-因為mysql_select_db僅返回布爾值。
編輯2:您可能的意思是:
$db = mysql_connect('localhost','root','saw123') or die("Connection error");
mysql_select_db("moviesite",$db) or die(myql_error($db));
在這種情況下,$ db不會被適當地命名; 它會更准確地稱為$ connection或$ db_connection或類似的名稱。
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