Android應用程序在phonegap中讀取設備信息

Question

我如何獲得以下這些項目從設備中讀取數據並在下面的html頁面中顯示？

  $('#devicename').html(device.name);
  $('#devicephonegap').html(device.phonegap);
  $('#devicplatform').html(device.platform);
  $('#deviceuuid').html(device.uuid);
  $('#deviceversion').html(device.version);

整頁代碼

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name="format-detection" content="telephone=no" />
<meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width, height=device-height, target-densitydpi=device-dpi" />
<link rel="stylesheet" type="text/css" href="jquery.mobile-1.2.0.css" />
<script type="text/javascript" src="jquery-1.8.2.js"></script>
<script type="text/javascript" src="jquery.mobile-1.2.0.js"></script>
<script type="text/javascript">

    $(document).on("pageinit", "#newpage", function () {
        $('#saveButton').click(function () {
            localStorage.setItem("name", $('#name').val());
        });


    });
    var wID = navigator.accelerometer.watchAcceleration(onSucess, onerror, { frequency: 1000 });
    function onSucess(a) {
        $('#aX').html(a.x);
        $('#aY').html(a.y);
        $('#aZ').html(a.z);
        $('#aTime').html(a.timestamp);
    }
    function onError() {

    }
var phoneName = window.device.name;
var phoneName = device.name;
        $('#devicename').html(device.name);
        $('#devicephonegap').html(device.phonegap);
        $('#devicplatform').html(device.platform);
        $('#deviceuuid').html(device.uuid);
        $('#deviceversion').html(device.version);


    $(document).on('pageshow', '#newpage', function () {
        var personName = localStorage.getItem("name");
        if (personName.length > 0) {
            $('#name').val(personName);
        }
    });
</script>
<title>Hello World 2</title>
</head>
<body>
<div id="home" data-role="page">
    <div data-role="header">
        <h1>Home Page2</h1>
    </div>
    <div data-role="content">
        hello Phone Gap and JQuery Mobile! 
        <a href="#newpage" data-role="button">new page</a>
        <br>
        <p id="devicename">  </p>
        <p id="devicephonegap">  </p>
        <p id="deviceplatform">  </p>
        <p id="deviceuuid">  </p>
        <p id="deviceversion">  </p>
         <p id="ax">  </p>
        <p id="ay">  </p>
        <p id="az">  </p>
        <p id="aTime">  </p>
    </div>
    <div data-role="footer" data-position="fixed">
    <a href="#dialogpage" data-rel="dialog" data-icon="plus">Add Something</a>

    </div>
</div>


<div id="newpage" data-role="page">
    <div data-role="header">
    <a href="#home" data-icon="delete">Cancel</a>
        <h1>New Page</h1>
        <a href=#home" data-icon="save">save</a>
    </div>
    <div data-role="content">
        <label for="name">what is your name?</label>
        <input id="name" type="text" name="name" value="" />
        <a id="saveButton" href="" data-role="button">Save</a>
    </div>
    <div data-role="footer" data-position="fixed">
        <h4>
            footer</h4>
    </div>
</div>

<div id="dialogpage" data-role="page"> 
 <div data-role="header">
        <h1>Dialog</h1>
    </div>
     <div data-role="content">
        this is a dialog
     </div>
</div>
<script type="text/javascript" src="cordova-2.1.0.js"></script>
<script type="text/javascript" src="js/index.js"></script>
<script type="text/javascript">
    app.initialize();
</script>
</body>
</html>

Answer 1

您需要包含Device插件並要求獲得Android READ_PHONE_STATE權限。 這清楚地記錄在：

http://docs.phonegap.com/en/2.1.0/cordova_device_device.md.html#Device_permissions

Answer 2

-您需要為AndroidManifest.xml文件添加READ_PHONE_STATE 權限。

Android應用程序在phonegap中讀取設備信息

問題描述

2 個解決方案

解決方案1
1 2012-10-30 17:33:26

解決方案2
1 2012-10-30 17:44:00

Android應用程序在phonegap中讀取設備信息

問題描述

2 個解決方案

解決方案1 1 2012-10-30 17:33:26

解決方案2 1 2012-10-30 17:44:00

解決方案1
1 2012-10-30 17:33:26

解決方案2
1 2012-10-30 17:44:00