SQL Server 2000查詢最大日期的總值和值

Question

我有這個RoomTable有價值

SID   Room   Date        APhase   BPhase   ACount  BCount
1     One    10/28/2012  4        5         3       6
2     One    10/29/2012  2        3        -1      -1
3     One    10/30/2012  4        5         7      -1
4     Two    10/28/2012  8        3         2       3
5     Two    10/30/2012  3        5         4       6
6     Three  10/29/2012  5        8         2      -1
7     Three  10/30/2012  5        6        -1       4
8     Four   10/29/2012  6        2        -1      -1
9     Four   10/30/2012  5        8        -1      -1

我想要的是返回以下內容：

1. 每個房間的APhase和BPhase的總和。
2. 每個房間最大日期的ACount和BCount的價值
3. 如果ACount值為-1，則使用上一個日期。 與BCount相同。
4. 如果ACount值為-1，前一個日期為-1，依此類推。 然后使用0.與BCount相同。

我可以使用此查詢獲得數字1的查詢

SELECT Room, sum(APhase) as TotalAPhase, sum(BPhase) as TotalBPhase 
FROM RoomTable 
WHERE Date between '10/28/2012' and '10/30/2012'
group by Room
order by Room

但我對如何包含2-4號查詢感到困惑。

這是我想要的輸出

Room  TotalAPhase  TotalBPhase  ACount   BCount
One   10           13           7        6
Two   11           8            4        6
Three 10           13           2        4
Four  11           10           0        0

任何想法將不勝感激。 謝謝。

Answer 1

希望這適用於您的情況：

SELECT 
Room
,SUM(APhase) AS TotalAPhase
,SUM(BPhase) AS TotalBPhase 
,ISNULL((    SELECT TOP 1 RT1.ACount 
             FROM RoomTable RT1 
             WHERE RT1.Room = RT.Room 
                AND RT1.ACount != -1
             ORDER BY RT1.Date DESC
), 0) AS ACount
,ISNULL((   SELECT TOP 1 RT2.BCount 
            FROM RoomTable RT2
            WHERE RT2.Room = RT.Room 
               AND RT2.BCount != -1
            ORDER BY RT2.Date DESC
), 0) AS BCount

FROM RoomTable RT
--WHERE Date between '10/28/2012' and '10/30/2012'
GROUP BY Room
ORDER BY Room

我不確定你是否真的需要where子句，所以我評論了它。 在結果表中，RoomB的TotalBPhase值應該是14，從這個SQL Fiddle演示中可以看出。

Answer 2

您可以使用@ yildizm85的答案，或者如果您需要更高性能的代碼，您可以分解較小步驟上的所有任務並使用表變量來實現相同的目標。 見下面的查詢......

declare @roomResult table
(Room nvarchar(50), maxadate datetime, maxbdate datetime, TotalAPhase int , TotalBPhase int , acount int, bcount int)

insert into @roomResult 
SELECT Room, null,null,sum(APhase) as TotalAPhase, sum(BPhase) as TotalBPhase ,0,0
FROM RoomTable 
group by Room
order by Room

update @roomresult 
set maxadate = mxdate  
from 
(
select room roomname, max( date) mxdate  from
(
select room, date , case when acount = -1 then null else acount end acount , case when bcount = -1 then null else bcount end bcount 
from roomtable ) as a where a.acount is not null
 group by room
) b inner join @roomresult c on b.roomname = c.room


update @roomresult 
set maxbdate = mxdate  
from 
(
select room roomname, max( date) mxdate  from
(
select room, date , case when bcount = -1 then null else bcount end bcount 
from roomtable ) as a where a.bcount is not null
 group by room
) b inner join @roomresult c on b.roomname = c.room

update @roomresult 
set acount = r.acount
from @roomresult rr inner join roomtable r
on rr.room = r.room and rr.maxadate = r.date

update @roomresult 
set bcount = r.bcount
from @roomresult rr inner join roomtable r
on rr.room = r.room and rr.maxbdate = r.date

select Room,TotalAPhase,TotalbPhase,ACount,BCount From @roomResult 

Answer 3

您可以嘗試查詢類似這樣的內容>>>

SELECT Room, sum(APhase) as TotalAPhase, sum(BPhase) as TotalBPhase 
FROM RoomTable 
WHERE Date =(select max(Date) from RoomTable group by Room order by Room)
and ACount=(update RoomTable set ACount=0 where ACount<0) and and ACount=(update RoomTable set BCount=0 where BCount<0)
group by Room 
order by Room