[英]How to turn JSON to object literal using PHP and jquery
是否有一種簡潔明了的方法將XML提要轉換為JavaScript對象文字?
我有這個XML feed
<jobs>
<industry>
<name>Technology</name>
<area>Refrigiration</area>
<area>Information Technology</area>
<area>Electronics</area>
<area>Avionics</area>
</industry>
<industry>
<name>Agriculture</name>
<area>Agri-Tourism</area>
<area>Animal Husbandry</area>
<area>Harvesting</area>
<area>Poultry</area>
</industry>
</jobs>
並希望將其轉換為:
var jobs = [
{
"name" : "Technology",
"areas" : [ "Refrigiration" , "Information Technology", "Electronics", "Avionics" ]
},
{
"name" : "Agriculture",
"areas" : [ "Agri-Tourism" , "Animal Husbandry", "Harvesting", "Poultry" ]
},
{
"name" : "Media",
"areas" : [ "Journalism" , "Camera person", "Reality tv person", "Commentator" ]
}
];
我成功地編碼使用PHP的JSON對象。 我所缺少的是其余的。
echo json_encode(simplexml_load_string("<jobs>
<industry>
<name>Technology</name>
<area>Refrigiration</area>
<area>Information Technology</area>
<area>Electronics</area>
<area>Avionics</area>
</industry>
<industry>
<name>Agriculture</name>
<area>Agri-Tourism</area>
<area>Animal Husbandry</area>
<area>Harvesting</area>
<area>Poultry</area>
</industry>
</jobs>"));
這給您:
{
"industry": [
{
"name": "Technology",
"area": [
"Refrigiration",
"Information Technology",
"Electronics",
"Avionics"
]
},
{
"name": "Agriculture",
"area": [
"Agri-Tourism",
"Animal Husbandry",
"Harvesting",
"Poultry"
]
}
]
}
您需要將XML轉換為數組https://stackoverflow.com/questions/4844476/xml-to-php-array
然后,您需要使用php將該數組轉換為json json_encode()
兩種解決方案:
純JQUERY
結合使用jQuery的parseXML和jQuery,您可以獲得所需的對象:
$.get("http://www.example.com/path/to/file.xml", function(data){
var xml = $.parseXML(data);
console.log(xml);
});
PHP + JQUERY
如果您已經將對象解析為json,只需將其打印到html文件中,然后使用jquery的getJSON獲取該文件
$.getJSON("http://www.example.com/json/feed",function(data){
console.log(data);
});
如果您在JavaScript回調中接收到JSON編碼的字符串,則可能需要運行$ .parseJSON()以使jQuery將其視為JSON對象而不是字符串
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