java.sql.SQLException參數索引超出范圍

Question

在使用此代碼時，它顯示java.sql.SQLException Parameter index out of range (1 > number of parameters, which is 0) ：

private void cmd_searchActionPerformed(java.awt.event.ActionEvent evt) {                                           
try{

 String sql = "select * from STD where Name like '%?%' ";
      pst=conn.prepareStatement(sql);
      pst.setString(1,TXT_STUDENTNAME.getText());
      String value=TXT_STUDENTNAME.getText();
      rs=pst.executeQuery();
       jTable1.setModel(DbUtils.resultSetToTableModel(rs));

             }catch(Exception e){
       JOptionPane.showMessageDialog(null,e);
   }        
}     

我怎樣才能從這個例外中恢復過來？

Answer 1

嘗試從sql中刪除通配符並將其添加到值：

String sql = "select * from STD where Name like ? ";
pst=conn.prepareStatement(sql);
pst.setString(1,"%"+TXT_STUDENTNAME.getText()+"%");

類似的問題在這里

Answer 2

private void cmd_searchActionPerformed(java.awt.event.ActionEvent evt) {                                           
try{

 String sql = "select * from STD where Name like '%?%' ";
      String strStudentName = TXT_STUDENTNAME.getText();
      pst=conn.prepareStatement(sql);
      pst.setString(1,strStudentName );
      rs=pst.executeQuery();
       jTable1.setModel(DbUtils.resultSetToTableModel(rs));

             }catch(Exception e){
       JOptionPane.showMessageDialog(null,e);
   }        
}  

我想這會對你有所幫助..

String strStudentName = TXT_STUDENTNAME.getText（）; pst.setString（1，strStudentName）;