[英]How to send SN when tree node is selected?
我有這個Primefaces樹:
JSF代碼
<h:form id="form">
<p:tree id="tree" value="#{TreeViewController.root}" var="node" dynamic="true" cache="true" animate="true"
selectionMode="single" selection="#{TreeViewController.selectedNode}" highlight="true">
<p:ajax event="select" listener="#{TreeViewController.onNodeSelect}" update=":form:outputComponent" />
<p:treeNode>
<h:outputText value="#{node}"/>
</p:treeNode>
</p:tree>
<p:outputPanel id="outputComponent">
<h:outputText value="#{TreeViewController.data}" />
</p:outputPanel>
</h:form>
托管豆
private TreeNode root;
private TreeNode selectedNode;
public TreeView() {
root = new DefaultTreeNode("Root", null);
TreeNode node0 = new DefaultTreeNode("Node 0", root);
TreeNode node1 = new DefaultTreeNode("Node 1", root);
TreeNode node2 = new DefaultTreeNode("Node 2", root);
TreeNode node3 = new DefaultTreeNode("Node 3", root);
TreeNode node4 = new DefaultTreeNode("Node 4", root);
TreeNode node00 = new DefaultTreeNode("Node 0.0", node0);
TreeNode node01 = new DefaultTreeNode("Node 0.1", node0);
TreeNode node02 = new DefaultTreeNode("Node 0.2", node0);
TreeNode node03 = new DefaultTreeNode("Node 0.3", node0);
TreeNode node04 = new DefaultTreeNode("Node 0.4", node0);
TreeNode node05 = new DefaultTreeNode("Node 0.5", node0);
TreeNode node06 = new DefaultTreeNode("Node 0.6", node0);
TreeNode node07 = new DefaultTreeNode("Node 0.7", node0);
TreeNode node08 = new DefaultTreeNode("Node 0.8", node0);
TreeNode node09 = new DefaultTreeNode("Node 0.9", node0);
TreeNode node10 = new DefaultTreeNode("Node 1.0", node1);
TreeNode node11 = new DefaultTreeNode("Node 1.1", node1);
TreeNode node000 = new DefaultTreeNode("Node 0.0.0", node00);
TreeNode node001 = new DefaultTreeNode("Node 0.0.1", node00);
TreeNode node010 = new DefaultTreeNode("Node 0.1.0", node01);
TreeNode node100 = new DefaultTreeNode("Node 1.0.0", node10);
}
public TreeNode getRoot() {
return root;
}
public String data;
public void onNodeSelect(NodeSelectEvent event) {
String node = event.getTreeNode().getData().toString();
data = node;
}
public String getData(){
return data;
}
public TreeNode getSelectedNode() {
return selectedNode;
}
public void setSelectedNode(TreeNode selectedNode) {
this.selectedNode = selectedNode;
}
我需要傳遞一個稱為序列號的值,該值稍后將用於SQL查詢以獲取所選節點的信息。 想法是為節點中的每個組件創建具有隱藏序列號的樹。 稍后,此SN將用於從數據庫獲取數據。 如何隱藏每個組件的此SN? 現在,我只能得到樹節點的名稱。
盡管我回復它還很晚,但它仍然可能對其他人有所幫助。 這是我所做的,
我已經完成了以下課程
class CustomizedTree{
private Integer id;
private String name;
public CustomizedTree(Integer id, String name){
this.id = id;
this.name = name;
}
/**
* @return the id
*/
public Integer getId() {
return id;
}
/**
* @param id the id to set
*/
public void setId(Integer id) {
this.id = id;
}
/**
* @return the name
*/
public String getName() {
return name;
}
/**
* @param name the name to set
*/
public void setName(String name) {
this.name = name;
}
}
在為樹節點對象添加類型時,
CustomizedTree t = null;
t = new CustomizedTree(device.getId(), device.getName());
TreeNode node0 = new TreeNodeImpl(t, root);
現在,通過這種方式,我也可以將Id傳遞給樹節點。
當選擇一個節點時,我同樣會檢索其ID。
CustomizedTree treeNode = (CustomizedTree)event.getTreeNode().getData();
FacesMessage msg = new FacesMessage(FacesMessage.SEVERITY_INFO, "Selected",treeNode.getName());
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