[英]Split list of tuples based on value within tuple
如果我有以下內容:
[(1,2),(2,3),(0,0),(4,0),(0,1),(3,9),(2,0),(2,4)]
我怎么能把它分成:
[(1,2),(2,3)], [(0,1),(3,9)], [(2,4),]
每當我看到索引為1的元組,例如(1,0)時,我就會分割列表。
嘗試這個:
from itertools import groupby
x = [(1,2), (2,3), (0,0), (4,0), (0,1), (3,9), (2,0), (2,4)]
print [l for l in [list(group) for key, group in groupby(x, key=lambda k: k[1]==0)]
if l[0][1] != 0]
[OUT] [[(1,2), (2,3)], [(0,1), (3,9)], [(2,4)]]
它會生成一個列表,您可以迭代以獲取這些子列表。
它不是特別光滑,但你可以像這樣循環它:
myList = [(1,2),(2,3),(0,0),(4,0),(0,1),(3,9),(2,0),(2,4)]
groupedList = []
subList = []
for tup in myList:
if tup[1] == 0:
if subList != []:
groupedList.append(subList)
subList = []
else:
subList.append(tup)
if subList != []:
groupedList.append(subList)
print groupedList
輸出:
[[(1, 2), (2, 3)], [(0, 1), (3, 9)], [(2, 4)]]
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.