[英]populate select element based on json
如何填充第二個選擇元素? 我已經弄清楚如何做第一個。 但是,根據選擇的“制作”,我該如何第二次執行相同的操作? 我試圖通過一些小小的步驟來講述自己,但是我認為這對我來說可能太高級了。
var cars = '{"USED":[{"name":"Acura","value":"20001","models":[{"name":"CL","value":"20773"},{"name":"ILX","value":"47843"},{"name":"ILX Hybrid","value":"48964"},{"name":"Integra","value":"21266"},{"name":"Legend","value":"21380"},{"name":"MDX","value":"21422"},{"name":"NSX","value":"21685"},{"name":"RDX","value":"21831"},{"name":"RL","value":"21782"},{"name":"RSX","value":"21784"},{"name":"SLX","value":"21879"},{"name":"TL","value":"22237"},{"name":"TSX","value":"22248"},{"name":"Vigor","value":"22362"},{"name":"ZDX","value":"32888"}]},{"name":"Alfa Romeo","value":"20047","models":[{"name":"164","value":"20325"},{"name":"8c Competizione","value":"34963"},{"name":"Spider","value":"22172"}]}';
var carobj = eval ("(" + cars + ")");
var select = document.getElementsByTagName('select')[0];
//print array elements out
for (var i = 0; i < carobj.USED.length; i++) {
var d = carobj.USED[i];
select.options.add(new Option(d.name, i))
};
如果我沒看錯您的問題,那么您想在第二選擇中填充第一選擇中制造商的模型。 請參閱下面的純JS方法(使用jsfiddle)。 如果可能的話,我建議使用jQuery,因為我更喜歡jQuery解決方案。
var carobj;
window.onload = function () {
var cars = '{"USED":[{"name":"Acura","value":"20001","models":[{"name":"CL","value":"20773"},{"name":"ILX","value":"47843"},{"name":"ILX Hybrid","value":"48964"},{"name":"Integra","value":"21266"},{"name":"Legend","value":"21380"},{"name":"MDX","value":"21422"},{"name":"NSX","value":"21685"},{"name":"RDX","value":"21831"},{"name":"RL","value":"21782"},{"name":"RSX","value":"21784"},{"name":"SLX","value":"21879"},{"name":"TL","value":"22237"},{"name":"TSX","value":"22248"},{"name":"Vigor","value":"22362"},{"name":"ZDX","value":"32888"}]},{"name":"Alfa Romeo","value":"20047","models":[{"name":"164","value":"20325"},{"name":"8c Competizione","value":"34963"}, {"name":"Spider","value":"22172"}]}]}';
carobj = eval ("(" + cars + ")");
var makes = document.getElementById('make');
for (var i = 0; i < carobj.USED.length; i++) {
var d = carobj.USED[i];
makes.options.add(new Option(d.name, i));
}
makes.onchange = getModels;
getModels();
}
// add models based on make
function getModels () {
var makes = document.getElementById('make');
var make = makes.options[makes.selectedIndex].text;
for (var i = 0; i < carobj.USED.length; i++) {
if (carobj.USED[i].name == make) {
var models = document.getElementById('model');
models.options.length = 0;
for (var j= 0; j < carobj.USED[i].models.length; j++) {
var model = carobj.USED[i].models[j];
models.options.add(new Option(model.name, j));
}
break;
}
}
}
我還建議您研究更安全的JSON解析。 如果在任何用戶輸入上運行eval,則存在安全風險。 您可以查看JSON.org及其json2.js 。 或者,如果您想使用jQuery: parseJSON 。 以下是jQuery版本:
jQuery.parseJSON(jsonString);
JSON解析技巧來自: 安全地將JSON字符串轉換為object 。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.