[英]How do I run a function in a Python module using only the Windows command line?
[英]How do I run a command in background using commands module in python?
我想使用 python 2.7 在后台運行系統命令,這就是我所擁有的:
import commands
path = '/fioverify.fio'
cmd= "/usr/local/bin/fio" + path + " "+ " &"
print cmd
handle = commands.getstatusoutput(cmd)
這失敗了。 如果我刪除&符號&
它的工作原理。 我需要在后台運行一個命令( /usr/local/bin/fio/fioverifypath
)。
有關如何完成此操作的任何指示?
不要使用commands
; 它已被棄用,實際上對您的目的沒有用。 改用subprocess
。
fio = subprocess.Popen(["/usr/local/bin/fio", path])
與您的進程並行運行fio
命令,並將變量fio
綁定到進程的句柄。 然后您可以調用fio.wait()
等待進程完成並檢索其返回狀態。
使用子進程模塊, subprocess.Popen
允許您將命令作為子進程(在后台)運行並檢查其狀態。
您也可以嘗試sh.py ,它支持后台命令:
import sh
bin = sh.Command("/usr/local/bin/fio/fioverify.fio")
handle = bin(_bg=True)
# ... do other code ...
handle.wait()
commands.getstatusoutput(...)
是不夠聰明處理后台進程,使用subprocess.Popen
或os.system
。
重現commands.getstatusoutput
如何在后台進程中失敗的錯誤:
import commands
import subprocess
#This sleeps for 2 seconds, then stops,
#commands.getstatus output handles sleep 2 in foreground okay
print(commands.getstatusoutput("sleep 2"))
#This sleeps for 2 seconds in background, this fails with error:
#sh: -c: line 0: syntax error near unexpected token `;'
print(commands.getstatusoutput("sleep 2 &"))
subprocess.Popen 如何在后台進程上成功的演示:
#subprocess handles the sleep 2 in foreground okay:
proc = subprocess.Popen(["sleep", "2"], stdout=subprocess.PIPE)
output = proc.communicate()[0]
print(output)
#alternate way subprocess handles the sleep 2 in foreground perfectly fine:
proc = subprocess.Popen(['/bin/sh', '-c', 'sleep 2'], stdout=subprocess.PIPE)
output = proc.communicate()[0]
print("we hung for 2 seconds in foreground, now we are done")
print(output)
#And subprocess handles the sleep 2 in background as well:
proc = subprocess.Popen(['/bin/sh', '-c', 'sleep 2'], stdout=subprocess.PIPE)
print("Broke out of the sleep 2, sleep 2 is in background now")
print("twiddling our thumbs while we wait.\n")
proc.wait()
print("Okay now sleep is done, resume shenanigans")
output = proc.communicate()[0]
print(output)
os.system 如何處理后台進程的演示:
import os
#sleep 2 in the foreground with os.system works as expected
os.system("sleep 2")
import os
#sleep 2 in the background with os.system works as expected
os.system("sleep 2 &")
print("breaks out immediately, sleep 2 continuing on in background")
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