產生10個隨機數

Question

我正在嘗試從數字數組中顯示10個隨機數，但均未成功。

這是我的代碼：

<?php
$num = array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", "2009");

//echo $num[rand(0,9)];
echo '<br/>';
for ($num = 2000; $num <= 10; $num[rand(0,9)]++)
{
    echo "The number is " . $num . "<br />";
}
?>

盡管我的ubuntu php.ini上有display_errors = On ，但腳本不顯示任何內容。

我要去哪里錯了？

Answer 1

只需使用array_rand ：

array_rand($num, 10); // returns a new array with 10 randomly selected values.

之后，您可以使用foreach遍歷這些：

$rand = array_rand($num, 10);

foreach($rand as $key) {
  echo "The number is " . $num[key] . "<br />";
}

Answer 2

我會改用shuffle功能。

<?php
$num = array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", "2009");
shuffle($num);
echo '<br/>';
foreach ($num as $value)
  {
  echo "The number is " . $value . "<br />";
  }
?>

Answer 3

嘗試shuffle（）

$num= array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", 
  "2009");

shuffle($num);

 //echo $num[rand(0,9)];
 echo '<br/>';
 for ($i = 0; $i < count($num); $i++)
 {
  echo "The number is " . $num[$i] . "<br />";
 }

Answer 4

您從$num = 2000開始循環，並在$num <= 10時停止。 因此它不會執行。

Answer 5

<?php
  $num= array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", 
  "2009");

 //echo $num[rand(0,9)];
 echo '<br/>';
 for ($i = 0; $i < count($num); $i++)
 {
  echo "The number is " . $num[rand(0, count($num))] . "<br />";
 }
?>

Answer 6

    $num= array("2000", "2001", "2002", "2003", "2004", "2005", "2006", "2007", "2008", "2009");

    for($i=0; $i<10; $i++){
        $rand = rand(0,count($num));
        echo "The number is " . $num[$rand] . "<br />";

        // unset($num[$rand]); //to get unique numbers each time .. this will unset array item after its showed
        // $num = array_values($num); //reindex after unset
    }

如果只想獲得唯一的結果，可以使用unset和array_values