排序字典對象的數組

Question

我的問題是我無法對NSMutableDictionary對象的NSMutableArray進行排序，我想按等級對對象進行排序，等級為NSNumber，我缺少什么？

我當前的代碼將“ arrayMealRating”中的所有評分相加，並對結果數組進行排序：

            [arrayMealRating addObject:[NSMutableDictionary dictionaryWithObjectsAndKeys:
                                        [eachObject objectForKey:@"Airline"], @"Airline"
                                        ,[eachObject objectForKey:@"setMealRating"], @"setMealRating"
                                        , nil]];

        }
        NSArray *airlineNames = [arrayMealRating valueForKeyPath:@"@distinctUnionOfObjects.Airline"];

        // Loop through all the airlines
        for (NSString *airline in airlineNames) {

            // Get an array of all the dictionaries for the current airline
            NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(Airline == %@)", airline];
            NSArray *airlineMealRating = [arrayMealRating filteredArrayUsingPredicate:predicate];

            // Get the sum of all the ratings using KVC @sum collection operator
            NSNumber *rating = [airlineMealRating valueForKeyPath:@"@sum.setMealRating"];

            //NSLog(@"%@: %@", airline, rating);
            [sortedMealArray addObject:[NSMutableDictionary dictionaryWithObjectsAndKeys:
                                        airline, @"Airline"
                                        ,[rating stringValue], @"setMealRating"
                                      , nil]];
        }



        NSSortDescriptor *descriptor = [[NSSortDescriptor alloc] initWithKey:@"setMealRating"  ascending:YES];
        [sortedMealArray sortedArrayUsingDescriptors:[NSMutableArray arrayWithObjects:descriptor,nil]];
        auxMealRating = [sortedMealArray copy];

如有疑問，請不要投下反對票，只問我即可編輯問題。

最好的問候，對不起，我英語不好。

Answer 1

這應該做您想要的：

NSArray *sortedArray = [arrayMealRating sortedArrayUsingComparator:^(id obj1, id obj2) {
    NSNumber *rating1 = [(NSDictionary *)obj1 objectForKey:@"setMealRating"];
    NSNumber *rating2 = [(NSDictionary *)obj2 objectForKey:@"setMealRating"];
    return [rating1 compare:rating2];
}];