MySQL LEFT OUTER JOIN 虛擬表

Question

我正在處理一個非常復雜的查詢，讓我試着向你解釋一下。 這是我在 MySQL 數據庫中的表：

學生表

--- `students` ---
student_id    first_name    last_name    current_status    status_change_date
------------  ------------  -----------  ----------------  --------------------
1             John          Doe          Active            NULL
2             Jane          Doe          Retread           2012-02-01

student_have_courses 表

--- `students_have_courses` ---
students_student_id    courses_course_id    s_date      e_date      int_date
---------------------  -------------------  ----------  ----------  -----------
1                      1                    2012-01-01  2012-01-04  2012-01-05
1                      2                    2012-01-05  NULL        NULL
2                      1                    2012-01-10  2012-01-11  NULL

student_have_optional_courses 表

--- `students_have_optional_courses` ---
students_student_id    optional_courses_opcourse_id    s_date      e_date
---------------------  ------------------------------  ----------  ----------
1                      1                               2012-01-02  2012-01-03
1                      1                               2012-01-06  NULL
1                      5                               2012-01-07  NULL

到目前為止，這是我的查詢

SELECT 
  `students_and_courses`.student_id,
  `students_and_courses`.first_name,
  `students_and_courses`.last_name,
  `students_and_courses`.courses_course_id,
  `students_and_courses`.s_date,
  `students_and_courses`.e_date,
  `students_and_courses`.int_date,
  `students_have_optional_courses`.optional_courses_opcourse_id,
  `students_have_optional_courses`.s_date,
  `students_have_optional_courses`.e_date
FROM (
  SELECT
    `c_s_a_s`.student_id,
    `c_s_a_s`.first_name,
    `c_s_a_s`.last_name,
    `c_s_a_s`.courses_course_id,
    `c_s_a_s`.s_date,
    `c_s_a_s`.e_date,
    `c_s_a_s`.int_date
 FROM (
   SELECT
      `students`.student_id,
      `students`.first_name,
      `students`.last_name,
      `students_have_courses`.courses_course_id,
      `students_have_courses`.s_date,
      `students_have_courses`.e_date,
      `students_have_courses`.int_date
    FROM
      `students`
      LEFT OUTER JOIN `students_have_courses`
        ON (
          `students_have_courses`.`students_student_id` = `students`.`student_id` AND     (( 
          `students_have_courses`.`s_date` >= `students`.`status_change_date` AND
          `students`.current_status = 'Retread' ) OR
          `students`.current_status = 'Active')
        )
      WHERE
        `students`.current_status = 'Active' OR
        `students`.current_status = 'Retread'
  ) `c_s_a_s`
  ORDER BY
    `c_s_a_s`.`courses_course_id` DESC
) `students_and_courses`
LEFT OUTER JOIN `students_have_optional_courses`
  ON (
    `students_have_optional_courses`.students_student_id =     `students_and_courses`.student_id AND
    `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND 
    `students_have_optional_courses`.e_date IS NULL
  )
GROUP BY
 `students_and_courses`.student_id;

我想要返回的是所有 Active 或 Retread 學生的 student_id、first_name 和 last_name，然后左加入最高的 course_id、s_date、e_date 和 int_date，這些學生的 s_date 從 status_change_date 開始，如果 status 為“Retread” '。 然后從students_have_optional_courses TABLE中LEFT JOIN最高的optional_courses_opcourse_id，s_date和e_date，其中students_have_optional_courses.s_date大於或等於students_have_courses.s_date並且students_have_optional_courses.e_date是NULL

這是返回的內容：

student_id    first_name    last_name    courses_course_id    s_date      e_date      int_date      optional_courses_opcourse_id    s_date_1    e_date_1
------------  ------------  -----------  -------------------  ----------  ----------  ------------  ------------------------------  ----------  ----------
1             John          Doe          2                    2012-01-05  NULL        NULL          1                               2012-01-06  NULL
2             Jane          Doe          NULL                 NULL        NULL        NULL          NULL                            NULL        NULL

這是我想要返回的內容：

student_id    first_name    last_name    courses_course_id    s_date      e_date      int_date      optional_courses_opcourse_id    s_date_1    e_date_1
------------  ------------  -----------  -------------------  ----------  ----------  ------------  ------------------------------  ----------  ----------
1             John          Doe          2                    2012-01-05  NULL        NULL          5                               2012-01-07  NULL
2             Jane          Doe          NULL                 NULL        NULL        NULL          NULL                            NULL        NULL

除了一件事，一切都在工作，無論我如何形成查詢，我似乎都無法獲得最高的 student_have_optional_courses.optional_courses_opcourse_id

抱歉，我在寫完所有內容后自己解決了這個問題，我認為它幫助我想到了解決方案。

這是解決方案查詢：

    SELECT 
      `students_and_courses`.student_id,
      `students_and_courses`.first_name,
      `students_and_courses`.last_name,
      `students_and_courses`.courses_course_id,
      `students_and_courses`.s_date,
      `students_and_courses`.e_date,
      `students_and_courses`.int_date,
      `students_optional_courses`.optional_courses_opcourse_id,
      `students_optional_courses`.s_date,
      `students_optional_courses`.e_date
    FROM (
      SELECT
        `c_s_a_s`.student_id,
        `c_s_a_s`.first_name,
        `c_s_a_s`.last_name,
        `c_s_a_s`.courses_course_id,
        `c_s_a_s`.s_date,
        `c_s_a_s`.e_date,
        `c_s_a_s`.int_date
      FROM (
        SELECT
          `students`.student_id,
          `students`.first_name,
          `students`.last_name,
          `students_have_courses`.courses_course_id,
          `students_have_courses`.s_date,
          `students_have_courses`.e_date,
          `students_have_courses`.int_date
        FROM
          `students`
          LEFT OUTER JOIN `students_have_courses`
            ON (
              `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( 
              `students_have_courses`.`s_date` >= `students`.`status_change_date` AND
              `students`.current_status = 'Retread' ) OR
              `students`.current_status = 'Active')
            )
          WHERE
            `students`.current_status = 'Active' OR
            `students`.current_status = 'Retread'
      ) `c_s_a_s`
      ORDER BY
        `c_s_a_s`.`courses_course_id` DESC
    ) `students_and_courses`
    LEFT OUTER JOIN (
      SELECT
        *
      FROM
        `students_have_optional_courses`
      ORDER BY
        `students_have_optional_courses`.optional_courses_opcourse_id DESC
    ) `students_optional_courses`
      ON (
        `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND
        `students_optional_courses`.s_date >= `students_and_courses`.s_date AND 
        `students_optional_courses`.e_date IS NULL
      )
    GROUP BY
     `students_and_courses`.student_id;

Answer 1

這是我自己調試時找到的答案：

    SELECT 
      `students_and_courses`.student_id,
      `students_and_courses`.first_name,
      `students_and_courses`.last_name,
      `students_and_courses`.courses_course_id,
      `students_and_courses`.s_date,
      `students_and_courses`.e_date,
      `students_and_courses`.int_date,
      `students_optional_courses`.optional_courses_opcourse_id,
      `students_optional_courses`.s_date,
      `students_optional_courses`.e_date
    FROM (
      SELECT
        `c_s_a_s`.student_id,
        `c_s_a_s`.first_name,
        `c_s_a_s`.last_name,
        `c_s_a_s`.courses_course_id,
        `c_s_a_s`.s_date,
        `c_s_a_s`.e_date,
        `c_s_a_s`.int_date
      FROM (
        SELECT
          `students`.student_id,
          `students`.first_name,
          `students`.last_name,
          `students_have_courses`.courses_course_id,
          `students_have_courses`.s_date,
          `students_have_courses`.e_date,
          `students_have_courses`.int_date
        FROM
          `students`
          LEFT OUTER JOIN `students_have_courses`
            ON (
              `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( 
              `students_have_courses`.`s_date` >= `students`.`status_change_date` AND
              `students`.current_status = 'Retread' ) OR
              `students`.current_status = 'Active')
            )
          WHERE
            `students`.current_status = 'Active' OR
            `students`.current_status = 'Retread'
      ) `c_s_a_s`
      ORDER BY
        `c_s_a_s`.`courses_course_id` DESC
    ) `students_and_courses`
    LEFT OUTER JOIN (
      SELECT
        *
      FROM
        `students_have_optional_courses`
      ORDER BY
        `students_have_optional_courses`.optional_courses_opcourse_id DESC
    ) `students_optional_courses`
      ON (
        `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND
        `students_optional_courses`.s_date >= `students_and_courses`.s_date AND 
        `students_optional_courses`.e_date IS NULL
      )
    GROUP BY
     `students_and_courses`.student_id;

我需要在 LEFT JOINING 之前選擇和訂購 Students_have_optional_courses 表。 我希望這有助於任何其他機構尋找這樣的答案。