[英]How to convert video file(.mp4) format into binary format in android?
我想在網絡服務器中上傳視頻。 我得到了我想以二進制格式傳遞文件的服務,我該怎么做?
我試圖在 base64 的幫助下將視頻文件轉換為二進制格式..?
public class binaryformat extends Activity {
private String strAttachmentCoded;
Button b1;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
b1=(Button)findViewById(R.id.button1);
b1.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View v)
{
// TODO Auto-generated method stub
File file = new File("/mnt/sdcard/C:/Program Files (x86)/Wowza Media Systems/Wowza Media Server 3.1.2/content/sample.mp4");
FileInputStream objFileIS = null;
try
{
objFileIS = new FileInputStream(file);
}
catch (FileNotFoundException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
ByteArrayOutputStream objByteArrayOS = new ByteArrayOutputStream();
byte[] byteBufferString = new byte[1024];
try
{
for (int readNum; (readNum = objFileIS.read(byteBufferString)) != -1;)
{
objByteArrayOS.write(byteBufferString, 0, readNum);
System.out.println("read " + readNum + " bytes,");
}
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
byte[] byteBinaryData = Base64.encode((objByteArrayOS.toByteArray()), Base64.DEFAULT);
strAttachmentCoded = new String(byteBinaryData);
}
});
}
}
我在我的 3 應用程序中體驗到,如果使用 XML 通過服務器發送 IMAGE 或 VIDEO,那會很好。 如果您想在 ANDROID 中上傳 IMAGE 或 VIDEO,最好以 XML 中的 base64 String 形式發送 IMAGE 或 VIDEO。
public static String uploadMultiplePhoto(String url, String xmlString) {
String responseString = "";
try {
//instantiates httpclient to make request
DefaultHttpClient httpclient = new DefaultHttpClient();
//url with the post data
HttpPost request = new HttpPost(url);
//convert parameters into JSON object
//JSONObject holder = new JSONObject(jsonObjString);
//passes the results to a string builder/entity
StringEntity se = new StringEntity(xmlString);
//sets the post request as the resulting string
request.setEntity(se);
//sets a request header so the page receving the request
//will know what to do with it
request.setHeader("Accept", "application/xml");
/*request.setHeader("Content-type", "application/xml");*/
//Handles what is returned from the page
ResponseHandler<String> responseHandler = new BasicResponseHandler();
responseString = httpclient.execute(request, responseHandler);
} catch (Exception exception) {
exception.printStackTrace();
}
return responseString;
}
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