尋找最常被擊中的人

Question

我是 SQL 的新手，正在嘗試學習它。 我遇到的一個問題是如何在表中找到某個人的最大特定出現次數。 我不確定查詢將如何將每個 ID 與另一個 ID 進行比較並跟蹤計數。 糟糕的解釋，但這里有一個數據集，希望能讓它更清楚。

players:
+--------+--------+
| pid    | name   |
+--------+--------+
| 1      | Tom    |
| 2      | Sam    |
| 3      | Dan    |
+--------+--------+

scores:
+--------+--------+--------+
| sid    | pid    | result |
+--------+--------+--------+
| 1      | 1      | miss   |
| 2      | 1      | hit    |
| 3      | 3      | hit    |
| 4      | 2      | miss   |
| 5      | 3      | hit    |
| 6      | 3      | hit    |
+--------+--------+--------+

預期的答案是 pid = 3，name = Dan，因為他在所有其他玩家中的點擊率最高。

Answer 1

Select
  p.pid,
  p.name
From (
  Select
    p.pid,
    p.name,
    count(*)
  From
    players p
      inner join
    scores s On
      p.pid = s.pid
  Where
    result = 'hit'
  Group By
    p.pid,
    p.name
  Order By
    count(*) Desc
  ) p
Where 
  rownum = 1;

http://sqlfiddle.com/#!4/03ba0/22

Answer 2

試試這個： SQLFiddle Demo

select  pid, hits from(
    Select p.pid, count(*) as hits FROM players p
    JOIN scores s
         ON p.pid = s.pid AND s.result = 'hit'
    GROUP BY p.pid
    ORDER By count(*) DESC
)
Where rownum <= 1

Answer 3

這也可能是一個解決方案：

select
  players.pid,
  players.name
from
  scores inner join players
  on scores.pid = players.pid
  and scores.result = 'hit'
group by players.pid, players.name
having count(*)=(select max(cnt)
                 from
                   (select pid, count(*) as cnt
                    from scores
                    where result='hit'
                    group by pid) t)

請注意，如果他們都有相同的點擊次數，這將返回多個玩家。 還要注意，如果玩家出現在分數表中但不在玩家表中，則不會顯示。