PHP BitWise權限和角色，或替代方法

Question

我正在做我的第一個應用程序，其中包含多個用戶的權限和角色。 我的理解是最好的方法是使用BitWise格式。 這是真的，還是有更好的選擇？

這是我當前的測試代碼，而且效果相當怪異。 如果有人可以闡明為什么會這樣，那么將不勝感激。

例：

$user = array('permissions' => 1); // This *should* return ONLY READ, (except it shows all)
$user = array('permissions' => 8); // Shows correct, FULL resources.

您可以使用它來測試代碼... http://writecodeonline.com/php/

define("PERM_R", 1);  # Read    
define("PERM_W", 2);  # Write   
define("PERM_E", 4);  # Edit    
define("PERM_D", 8);  # Delete  

define("ROLE_GUEST",  PERM_R);
define("ROLE_EDITOR", ROLE_GUEST | PERM_W | PERM_E);
define("ROLE_FULL",   ROLE_EDITOR | PERM_D);

function hasAccess($user, $action) {
    if( is_array($user) ) {
        return $user['permissions'] & $action;
    } else if ( is_int($user) ) {
        return $user & $action;
    }
}


$user = array('permissions' => 1);
echo "USER PERMISSIONS: ". $user['permissions'] ."<br /><br />";

# TEST PERMS
if(hasAccess($user, PERM_R)) {
    echo PERM_R;
    echo " - Yes you can see READ <br />";
}
if(hasAccess($user, PERM_R | PERM_W)) {
    echo PERM_R | PERM_W;
    echo " - Yes you can see READ & WRITE<br />";
}
if(hasAccess($user, PERM_R | PERM_W | PERM_E)) {
    echo PERM_R | PERM_W | PERM_E;
    echo " - Yes you can see READ & WRITE & EDIT<br />";
}
if(hasAccess($user, PERM_R | PERM_W | PERM_E | PERM_D)) {
    echo PERM_R | PERM_W | PERM_E | PERM_D;
    echo " - Yes you can see READ & WRITE & EDIT & DELETE<br />";
}

# TEST ROLES
if(hasAccess($user, ROLE_GUEST)) {
    echo ROLE_GUEST;
    echo " - Yes, You Are A GUEST <br />";
}
if(hasAccess($user, ROLE_EDITOR)) {
    echo ROLE_EDITOR;
    echo " - Yes, You Are A EDITOR <br />";
}
if(hasAccess($user, ROLE_FULL)) {
    echo ROLE_FULL;
    echo " - Yes, You Are A FULL <br />";
}

Answer 1

問題是您只返回按位&的結果，對於所有測試，結果至少為1/true因為所有用戶都具有R權限。

1. 只向hasAccess()提供一個權限，停止使用| 。
2. 編寫一個新函數來確定進行整數比較的用戶級別。