org.apache.http.client.ClientProtocolException

Question

我已經制作了一個Android應用程序，它使用X509證書（位於文件夾res / raw / mykeystore.bks中）來簽署到9006端口上響應的遠程服務器。

服務器要求我登錄（用戶名，密碼）。

當我創建一個HTTPGet時，我有以下的例外：org.apache.http.client.ClientProtocolException

這是我的實現：

主要活動：

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Button b= (Button) findViewById(R.id.button1);
    b.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {               
             CredentialsProvider credProvider = new BasicCredentialsProvider();
                credProvider.setCredentials(new AuthScope(AuthScope.ANY_HOST, AuthScope.ANY_PORT),
                    new UsernamePasswordCredentials("rat#1", "rat"));
            HttpClient client = new MyHttpClient(getApplicationContext());
               ((AbstractHttpClient) client).setCredentialsProvider(credProvider);

               //final String url = "https://211.92.106.38:9006/KPIRest/testKpi/6";
               final String url = "https://211.92.106.38/KPIRest/testKpi/6";
               HttpGet httpGet = new HttpGet(url);

               try {
                HttpResponse response = client.execute(httpGet);
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
    });

自定義客戶端類：

public class MyHttpClient extends DefaultHttpClient {

final Context context;

public MyHttpClient(Context context) {
    this.context = context;
}

@Override
protected ClientConnectionManager createClientConnectionManager() {

        KeyStore trustStore = null;
            trustStore = KeyStore.getInstance("BKS");

        InputStream in = context.getResources().openRawResource(R.raw.mykeystore);
        try {
            // Initialize the keystore with the provided trusted certificates
            // Also provide the password of the keystore
            trustStore.load(in, "root01".toCharArray());
        } 
        } finally {

                in.close();

        }

        SSLSocketFactory sf=null;

            sf = new MySSLSocketFactory(trustStore);

        sf.setHostnameVerifier(SSLSocketFactory.ALLOW_ALL_HOSTNAME_VERIFIER);

        HttpParams params = new BasicHttpParams();
        HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
        HttpProtocolParams.setContentCharset(params, HTTP.UTF_8);

        SchemeRegistry registry = new SchemeRegistry();
        registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
        registry.register(new Scheme("https", sf, 9006));
    return new SingleClientConnManager(params, registry);
}
}

我的Customc SSLSoketFactory類：

public class MySSLSocketFactory extends SSLSocketFactory {
SSLContext sslContext = SSLContext.getInstance("TLS");

public MySSLSocketFactory(KeyStore truststore) throws NoSuchAlgorithmException, KeyManagementException, KeyStoreException, UnrecoverableKeyException {
    super(truststore);

    TrustManager tm = new X509TrustManager() {
        public void checkClientTrusted(X509Certificate[] chain, String authType) throws CertificateException {
        }

        public void checkServerTrusted(X509Certificate[] chain, String authType) throws CertificateException {
        }

        public X509Certificate[] getAcceptedIssuers() {
            return null;
        }
    };

    sslContext.init(null, new TrustManager[] { tm }, null);
}

@Override
public Socket createSocket(Socket socket, String host, int port, boolean autoClose) throws IOException, UnknownHostException {
    return sslContext.getSocketFactory().createSocket(socket, host, port, autoClose);
}

@Override
public Socket createSocket() throws IOException {
    return sslContext.getSocketFactory().createSocket();
}
}

我的申請有什么問題？ 什么原因導致異常？

謝謝你們！

編輯：

我看起來更好的例外：

cause = org.apache.http.auth.MalformedChallengeException：身份驗證質詢為空。

編輯2：

我試着使用這個實現沒有區別，我有同樣的例外！

編輯3：我已經更換了

 CredentialsProvider credProvider = new BasicCredentialsProvider();
                credProvider.setCredentials(new AuthScope(AuthScope.ANY_HOST, AuthScope.ANY_PORT),
                    new UsernamePasswordCredentials("rat#1", "rat"));

客戶端）.setCredentialsProvider（credProvider）;

使用基本httpclient autentication，將標題Authorization添加到httpGet：

  httpGet.addHeader("Authorization", "Basic "+Base64.encodeToString("rat#1:rat".getBytes(),Base64.DEFAULT));

現在服務器發給我這條消息：

HTTP/1.1 400 Bad Request 

Answer 1

問題是Authorization標頭。

我們必須使用：

httpGet.addHeader("Authorization", "Basic "+Base64.encodeToString("rat#1:rat".getBytes(),Base64.NO_WRAP));

代替：

httpGet.addHeader("Authorization", "Basic "+Base64.encodeToString("rat#1:rat".getBytes(),Base64.DEFAULT));

因為DEFAULT參數在字符串的末尾添加“CR”行終止符，如果你將它用於那個標題則它是不正確的。