使用CGRectMake移動子視圖會導致崩潰

Question

我試圖通過單擊按鈕來移動子視圖，但是它崩潰了，並給了我-[MainGameDisplay openTimeChanger:]: unrecognized selector sent to instance 0x10e443d0

這是我在做什么：

@interface:
UIImageView *changerBackground;
@implementation

timerView = [[UIView alloc] initWithFrame:CGRectMake(0, 278, 105, 27)];
[self.view addSubview:timerView];

changerBackground = [[UIImageView alloc] init];
[changerBackground setImage:[UIImage imageNamed:@"speedbackground.png"]];
changerBackground.frame = CGRectMake(-12 , 9, 105, 33);
[changerBackground setUserInteractionEnabled:YES];
[timerView addSubview:changerBackground];

UIButton *timerBackground = [UIButton buttonWithType:UIButtonTypeCustom];
[timerBackground setBackgroundImage:[UIImage imageNamed:@"Time Background.png"] forState:UIControlStateNormal];
[timerBackground setBackgroundImage:[UIImage imageNamed:@"Time Background.png"] forState:UIControlStateHighlighted];
[timerBackground addTarget:self action:@selector(openTimeChanger:) forControlEvents:UIControlEventTouchUpInside];
timerBackground.frame = CGRectMake(-2 , 15, 102, 27);
[timerView addSubview:timerBackground];



-(void)openTimeChanger {
    [UIView animateWithDuration:0.2f
                     animations:^{
                         changerBackground.frame = CGRectMake(-12 , -16, 105, 33);
                     }
                     completion:Nil];
}

還要注意changerBackground有3個子視圖。

Answer 1

你需要改變這個

[timerBackground addTarget:self action:@selector(openTimeChanger:) forControlEvents:UIControlEventTouchUpInside];

至

[timerBackground addTarget:self action:@selector(openTimeChanger) forControlEvents:UIControlEventTouchUpInside]; //note that semicolon is not there in the method name

您的方法定義是-(void)openTimeChanger而不是-(void)openTimeChanger:(id)sender 。 它試圖找到具有此定義的方法，但該方法不可用，因此導致崩潰。

如果要使用[timerBackground addTarget:self action:@selector(openTimeChanger:) forControlEvents:UIControlEventTouchUpInside]; ，然后將您的方法更改為-(void)openTimeChanger:(id)sender 。