提交后不顯示任何內容

Question

在下面的代碼中，我正在顯示JavaScript驗證。 但是當我單擊moduleSubmit按鈕時， if (isset($_POST['moduleSubmit'])) {之后，它什么都不顯示。 我的問題是，當我單擊按鈕並且JavaScript驗證已通過時，提交后如何顯示表單？

的JavaScript

function validation() {

    var isDataValid = true;

    var courseTextO = document.getElementById("coursesDrop");
    var moduleTextO = document.getElementById("modulesDrop");

    var errModuleMsgO = document.getElementById("moduleAlert");

    if (courseTextO.value == "") {
        $('#targetdiv').hide();
        $('#assessmentForm').hide();
        $('#updateForm').hide();
        $('#submitupdatebtn').hide();
        errModuleMsgO.innerHTML = "Please Select a Course";
        isDataValid = false;
    } else {
        errModuleMsgO.innerHTML = "";
    }

    if(isDataValid){
        $("#myForm").submit();
    }

}​

PHP / HTML

       <?php

// connect to the database
include('connect.php');


/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    die();
}


$sql = "SELECT CourseId, CourseNo, CourseName FROM Course ORDER BY CourseId"; 

$sqlstmt=$mysqli->prepare($sql);

$sqlstmt->execute(); 

$sqlstmt->bind_result($dbCourseId, $dbCourseNo, $dbCourseName);

$courses = array(); // easier if you don't use generic names for data 

$courseHTML = "";  
$courseHTML .= '<select name="courses" id="coursesDrop">' . PHP_EOL; 
$courseHTML .= '<option value="">Please Select</option>' . PHP_EOL;  

$outputcourse = "";

while($sqlstmt->fetch()) 
{

    $course = $dbCourseId;
    $courseno = $dbCourseNo;
    $coursename = $dbCourseName; 

    $courseHTML .= "<option value='" . $course . "'>" . $courseno . " - " . $coursename . "</option>" . PHP_EOL;  

    if (isset($_POST['courses']) && ($_POST['courses'] == $course)) {
        $outputcourse = "<p><strong>Course:</strong> " . $courseno .  " - "  . $coursename . "</p>";
    }

} 

$courseHTML .= '</select>'; 

?>

<form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" onsubmit="return validation();">
    <table>
        <tr>
            <th>Course: <?php echo $courseHTML; ?></th>
        </tr>
    </table>
    <p>
        <input id="moduleSubmit" type="submit" value="Submit Course and Module" name="moduleSubmit" />
    </p>
    <div id="moduleAlert"></div>
    <div id="targetdiv"></div>
</form>


<?php

if (isset($_POST['moduleSubmit'])) {    

    $sessionquery = "
    SELECT SessionId, SessionName, SessionDate, SessionTime, CourseId, SessionActive
    FROM Session
    WHERE (CourseId = ? AND SessionActive = ?)
    ORDER BY SessionName 
    ";

    $active = 1;

    $sessionqrystmt=$mysqli->prepare($sessionquery);
    // You only need to call bind_param once
    $sessionqrystmt->bind_param("si",$course, $active);
    // get result and assign variables (prefix with db)

    $sessionqrystmt->execute(); 

    $sessionqrystmt->bind_result($dbSessionId,$dbSessionName,$dbSessionDate,$dbSessionTime, $dbCourseId, $dbSessionActive);

    $sessionqrystmt->store_result();

    $sessionnum = $sessionqrystmt->num_rows();   

    if($sessionnum == 0) {
        echo "<p><span style='color: red'>Sorry, You have No Assessments under this Module</span></p>";
    } 
    else 
    { 
        echo "";
    }

    ...

}

Answer 1

您必須以html形式使用重定向操作。該操作會將您重定向到您想要的任何位置。

if $valid=$form->validate();
{
  $this->redirect('form url')
}

Answer 2

恐怕輸入type=button的值不會以表格形式發布。 您可以使用Firefox的firebug插件或chrome中的Developer工具來檢查http請求中的發布值。 或者，您也可以print_r($_POST)來查看在php端發布了哪些值。

嘗試使用隱藏的輸入<input type="hidden" value="1" name="issubmit"/>來檢查它是否是帖子。