[英]PHP Search Script for Website
好吧,所以我想為我的網站編寫一些PHP搜索腳本,以便用戶可以簡單地從歌手姓名,歌曲名稱或城市進行搜索。 我數據庫中的表包含“城市”,“藝術家”和“城市”。
這是我的表格:
<div id="search">
<form name="search" method="post" action="../searchDb.php">
<input type="text" name="find" placeholder="What are we searching for ?"/> in
<Select NAME="field">
<Option VALUE="artist">Artist</option>
<Option VALUE="song">Song</option>
<Option VALUE="city">City</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
</div>
如您所見,有三個OPTION值(表中的每一列一個)。 這是我的PHP代碼:
<?php
$searching = "searching";
$find = "find";
$field = "field";
//this is to make sure the user entered content
if ($searching =="yes")
{
echo "<p><h2>Results</h2></p>";
//if user did not enter anything in the search box, give error
if ($find == "")
{
echo "<p>You forgot to enter a search term</p>";
}
include 'connect.php';
// strip whitespace, non case sensitive
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//perform search in specified field
$data = mysql_query("SELECT * FROM artists_table WHERE upper($field) LIKE'%$find%'");
//show results
while($result = mysql_fetch_array( $data ))
{
echo $result['artist'];
echo " ";
echo $result['song'];
echo "<br>";
echo $result['city'];
echo "<br>";
echo "<br>";
}
//counts results. ifnone. error
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
//show user what he searched.
echo "<b>Searched For:</b> " .$find;
}
?>
我的connect.php(包括在內)可以完美工作(我在另一個頁面上使用了相同的文件,沒有問題..因此可以肯定地說那不是問題)。
當我進行測試並運行搜索時,它加載了我的searchDb.php,但未顯示任何內容。 只是一張白紙...
任何幫助將不勝感激。 我不知道為什么或什么不起作用...謝謝大家!
如果這是您的代碼,那么您將對$searching = "searching"
進行硬編碼,但是if
正在檢查$searching =="yes"
,則將不會顯示任何代碼。
<?php
$searching = "searching";
...
...
//this is to make sure the user entered content
if ($searching =="yes")
{
...
}
編輯-
我的猜測是您想做類似的事情-
$searching = mysql_real_escape_string($_POST['searching']); // sanitized just to be consistant.
$find = mysql_real_escape_string($_POST['find']);
$field = mysql_real_escape_string($_POST['field']);
注意-您不應該使用mysql_*
函數編寫新代碼。 您應該學習mysqli_
或PDO
- http: mysqli_
這是避免獲得“注意:未定義的變量”的兩種方法
檢查是否按下了submit
按鈕
if (isset($_POST['search'])) {
$searching = mysql_real_escape_string($_POST['searching']); // sanitized just to be consistant.
$find = mysql_real_escape_string($_POST['find']);
$field = mysql_real_escape_string($_POST['field']);
}
或檢查是否設置了每個字段,並將其設置為值,如果未設置為no / empty
if (isset($_POST['search'])) { // checks to see if the form submit button was pushed
$searching = isset($_POST['search']) ? mysql_real_escape_string($_POST['searching']) : 'no'; // sanitized just to be consistant.
$find = isset($_POST['find']) ? mysql_real_escape_string($_POST['find']) : '';
$field = isset($_POST['field']) ? mysql_real_escape_string($_POST['field']) : '';
}
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