Ruby中的正則表達式字符串解析

Question

我有這個設置（點數可變，這里2）：

A 
 This is some Text belonging to A
 This also belongs to A
B 
 This should be with B
 same with this
...
...

我希望它最終成為這樣的字符串：

A This is some Text belonging to A This also belongs to A
B This should be with B same with this

我的嘗試是這樣的：

answer.scan(/^([A-Z].+?(?=^[A-Z]))/m).map { |d| d.delete("\n") }.join("\n")

問題在於這與最后一組不匹配（您可以假定字符串以最后一組結尾）有什么想法嗎？ :)

edit1：修復了coyping錯誤，並在Rubular中嘗試了新的正則表達式，這是一種什么樣的工作，但是仍然有一些不必要的匹配項？

Answer 1

text = <<EOS
A 
 This is some Text belonging to A
 This also belongs to A
B 
 This should be with B
 same with this
 variable line
EOS

text.gsub(/\s?\n\s/, ' ')

# Outputs: 
# A This is some Text belonging to A This also belongs to A
# B This should be with B same with this variable line

Answer 2

answer = answer
.scan(/^([A-Z].+?(?=^[A-Z]))|(^[A-Z].+?\Z)/m)
.map {|item| item.reject { |i| i.nil? } }
.map { |d| d[0].delete("\n") }
.join("\n")

似乎暫時起作用...雖然可能不是最好的方法