SQL減去查詢中前一行的值的最佳方法？

Question

我正在嘗試計算數據庫中丟失的機器總時間。 表中的列是MachineID aka PlantID，StartTime，EndTime。

從理論上講，它只需按machineID和StartTime對表進行排序，然后采用當前行的StartTime並減去先前行的EndTime。

這是我目前有效的查詢：

SELECT SUM([StartTime] - [EndTime]) AS TotalLostTime  
FROM(SELECT * 
     FROM (SELECT ROW_NUMBER() OVER (ORDER BY [PlantID], [StartTime]) AS [Row],
                  [MachineRecords].PlantID , [MachineRecords].EndTime 
           FROM [MachineRecords]) AS a 
     JOIN (SELECT * 
           FROM (SELECT ROW_NUMBER() OVER (ORDER BY [PlantID], 
                                                        [StartTime]) AS [Row1],
                        [MachineRecords].PlantID as PlantID1 , 
                        [MachineRecords].StartTime 
                 FROM [MachineRecords]) as b) m 
     ON m.PlantID1 = a.[PlantID] 
        AND a.[Row] = m.[Row1]-1) lostTimeQuery

我的問題是：是否有更好的方法（更簡潔）來實現此查詢的相同結果？

謝謝您的幫助。

編輯：

從wildplasser發表評論后，我創建了以下查詢：

SELECT SUM(a.StartTime - a.LagEnd) as LostTime 
FROM (SELECT [PlantID], [StartTime], [EndTime], 
             LAG([PlantID]) OVER (ORDER BY PlantID, StartTime) LagPlantID,
             LAG([EndTime]) OVER (ORDER BY PlantID, StartTime) LagEnd 
      FROM MachineRecords) a 
WHERE a.PlantID = a.LagPlantID

Answer 1

這是我去的結果查詢:)

SELECT SUM(a.StartTime - a.LagEnd) as LostTime 
FROM (SELECT [PlantID], [StartTime], [EndTime], 
             LAG([PlantID]) OVER (ORDER BY PlantID, StartTime) LagPlantID,
             LAG([EndTime]) OVER (ORDER BY PlantID, StartTime) LagEnd 
      FROM MachineRecords) a 
WHERE a.PlantID = a.LagPlantID