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為什么這個jquery ajax調用不從我的PHP腳本返回數據?

[英]Why is this jquery ajax call not returning data from my php script?

我是jQuery的新手,無法在Firebug中調試此Ajax調用:

這是我的ajax電話:

var styndx = $('#studylist option:selected').val();
var studyname = $('#edit_field').val();


$.post("saveStudyName.php", {'type': 'update', 'studyname':studyname, 'styndx':styndx},
    function(resultmsg) {
    $('#edit_field').val('');
    $('#savebtn').attr('disabled',true);
    refresh_studynames();
});

這是函數refresh_studynames:

function refresh_studynames()
{
  $.ajax({                                      
     url: 'getStudyNames.php',                  
     data: "",                                                             
     dataType: 'json',               
          error: function() {
            alert('Refresh of study names failed.');
          },
     success: function(data)
     {
        $data.each(data, function(val, sname) {
        $('#studylist').append( $('<option></option>').val(val).html(sname) )
      });
     } 
  });
}

最后,這是php腳本getStudyNames.php($ dbname,$ dbconnect,$ hostname都已填充,並且$ dbconnect有效;后端數據庫是Postgres,而pg_fetch_all是PHP中的Postgres函數,它以數組形式返回結果):

$dbconnect = pg_pconnect("host=".$hostname." user=".$dbuser." dbname=".$dbname);    
    if (!$dbconnect)    {
        showerror(0,"Failed to connect to database",'saveStudyName',30,"username=".$dbuser.", dbname=".$dbname);
        exit;
    }

    $sql = "SELECT ST.studyindex,ST.studyabrv AS studyname
            FROM ibg_studies ST
            ORDER BY studyname";


    $fetchresult = pg_exec($dbconnect, $sql);
    if ($fetchresult) {
        $array = pg_fetch_all($fetchresult);
        echo json_encode($array);
    } else {
        $msg = "Failure! SQL="+$sql;
        echo $msg;
    }

任何幫助,不勝感激....

$('#studylist').append( $('<option></option>').val(val).html(sname) );

看起來錯了。

我不太確定,但是您可以嘗試:

var $studylist = $('#studylist').empty();
$data.each(data, function(i, record) {
    $studylist.append( $('<option/>').html(record.sname) );
});

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