[英]sql filter many to many relationship
我有下表
competitions
id prize
1 win a car
2 win an ipod
competition_type
competition_id Type_id
1 1
1 2
2 1
Type
id type
1 facebook
2 twitter
我該如何選擇所有不是Facebook的比賽,而是不是Twitter的比賽。 所以我應該獲得Win ipod作為最終結果?
查詢如何:
Select Prize from
Competitions a inner join competition_type b on a.id=b.competition_id
inner join Type c on b.Type_id=c.id
Where c.Type='facebook' and c.Type<>'twitter'
SELECT
ct.competition_id FROM
competitions c
JOIN competition_type ct ON ct.competition_id = c.id AND ct.Type_id = 1
WHERE
NOT EXISTS(SELECT * FROM competitions c2
JOIN competition_type ct2
ON ct2.competition_id = c2.id AND ct2.Type_id = 2
WHERE c2.id = c.id)
嘗試這個 -
select cmp.id, cmp.prize from
competitions cmp inner join competition_type ct on cmp.id = ct.competition_id
inner join Type t on t.id = ct.type_id
where t.type = 'facebook'
SELECT a.*
FROM competition a
WHERE a.id NOT IN
(
SELECT b.competition_id
FROM competition_type b
INNER JOIN Type c
ON b.type_ID = c.id
WHERE c.type = 'twitter'
)
請看這個例子
select * from Competitions as c
left join competition_type as ct
on c.id = ct.competition_id
left join Type as t
on t.id = ct.Type_id
where t.Type <> 'Twitter'
;
結果:
ID PRIZE COMPETITION_ID TYPE_ID TYPE
1 win a car 1 1 facebook
2 win an ipod 2 1 facebook
**用<> Twitter
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