SQL Oracle：如何在列中查找加工特定id的記錄

Question

我的查詢是：

select A.* 
  from (select r.role_id, 
               r.role_name, 
               r.active, 
               decode( r.entity_type_id, 1000, m.name, 3000, cour.name, 4000, 'Ensenda' ) companyName,
               LISTAGG(p.permission_id, ' | ') WITHIN GROUP (ORDER BY r.role_id) permission_id, 
               LISTAGG(p.permission_name, ' | ') WITHIN GROUP (ORDER BY r.role_id) permission_name, 
               row_number() over (order by r.created_ts desc) as RN, 
               count(*) over () as TOTAL_ROWS, 
               r.created_ts roleCreated 
          from t_role r
          left join t_role_permission rp ON r.role_id = rp.role_id
          left join t_permission p ON rp.permission_id = p.permission_id
          left join merchant m on r.entity_id = m.merchantkey 
          left join courier cour on r.entity_id = cour.courierkey 
         where 1=1
         --and p.permission_id =301446
         group by r.role_id, r.role_name, r.active, r.created_ts,
               decode( r.entity_type_id, 1000, m.name, 3000, cour.name, 4000, 'Ensenda' ) 
      ) A 
where RN between 1 and 100 order by roleCreated desc

我的結果是：

現在我想在permission_id的基礎上過濾列表，這樣我希望在permission_id列中列出與permission_id匹配的所有記錄。

例如：假設我為permission_id= 301446做了一個過濾器。 我想要以下結果

PS：在where子句中添加和p.permission_id=301446將不會產生所需的結果。

Answer 1

根據PasserBy評論回答

select A.* from(select r.role_id, r.role_name, r.active, 
decode( r.entity_type_id, 1000, m.name, 3000, cour.name, 4000, 'Ensenda' ) companyName,
LISTAGG(p.permission_id, ' | ') WITHIN GROUP (ORDER BY r.role_id) permission_id, 
LISTAGG(p.permission_name, ' | ') WITHIN GROUP (ORDER BY r.role_id) permission_name, 
row_number() over (order by r.created_ts desc) as RN, count(*) over () as TOTAL_ROWS, r.created_ts roleCreated 
from t_role r
left join t_role_permission rp ON r.role_id = rp.role_id
left join t_permission p ON rp.permission_id = p.permission_id
left join merchant m on r.entity_id = m.merchantkey 
left join courier cour on r.entity_id = cour.courierkey 
where 1=1

group by r.role_id, r.role_name, r.active, r.created_ts,
decode( r.entity_type_id, 1000, m.name, 3000, cour.name, 4000, 'Ensenda' ) 
)A where RN between 1 and 100 
and REGEXP_LIKE(a.permission_id,'(^|\s)301446(\s|$)')
order by roleCreated desc;

Answer 2

對於大型數據集，其中您要查找的permission_id的值不常見，查詢整個數據集然后對聚合結果進行過濾將是非常低效的，並且看起來似乎是邏輯上不正確的結果。

您要查找的內容不是權限ID列表包含特定值的角色列表，而是包含特定權限的角色的權限ID列表。 從邏輯上講，它最終的結果是相同的，但更符合問題的邏輯實現似乎總是帶來可讀性和（奇怪的）性能優勢。

無論如何，我確信你最好過濾到包含所需權限的角色，然后只為它們運行查詢：

 select A.* 
   from (select r.role_id, 
                r.role_name, 
                r.active, 
                decode( r.entity_type_id, 1000, m.name, 3000, cour.name, 4000, 'Ensenda' ) companyName,
                LISTAGG(p.permission_id, ' | ') WITHIN GROUP (ORDER BY r.role_id) permission_id, 
                LISTAGG(p.permission_name, ' | ') WITHIN GROUP (ORDER BY r.role_id) permission_name, 
                row_number() over (order by r.created_ts desc) as RN, 
                count(*) over () as TOTAL_ROWS, 
                r.created_ts roleCreated 
           from t_role r
           left join t_role_permission rp ON r.role_id = rp.role_id
           left join t_permission p ON rp.permission_id = p.permission_id
           left join merchant m on r.entity_id = m.merchantkey 
           left join courier cour on r.entity_id = cour.courierkey 
          where 1=1
            and r.role_id in (
                select role_id
                from   t_role_permission
                where  permission_id =301446)
          group by r.role_id, r.role_name, r.active, r.created_ts,
                decode( r.entity_type_id, 1000, m.name, 3000, cour.name, 4000, 'Ensenda' ) 
       ) A 
 where RN between 1 and 100 order by roleCreated desc

Answer 3

作為regexp_like路由的替代方法，您可以使用分析查詢（特別是listagg()的分析版本 ，並使用dense_rank()生成限制“行號”值來實現此目的：

select distinct role_id, role_name, active, companyName, permission_id,
    permission_name, rn, total_rows, roleCreated
from (
    select *
    from (
        select r.role_id, 
            r.role_name, 
            r.active, 
            decode(r.entity_type_id, 1000, m.name, 3000, cour.name,
                4000, 'Ensenda') companyName,
            p.permission_id as raw_permission_id,
            listagg(p.permission_id, ' | ')
                within group (order by p.permission_id)
                    over (partition by r.role_id) permission_id, 
            listagg(p.permission_name, ' | ')
                within group (order by p.permission_id)
                    over (partition by r.role_id) permission_name, 
            dense_rank() over (order by r.created_ts desc) as rn,
            count(distinct r.role_id) over () as total_rows, 
            r.created_ts roleCreated
        from t_role r
        left join t_role_permission rp ON r.role_id = rp.role_id
        left join t_permission p ON rp.permission_id = p.permission_id
        left join merchant m on r.entity_id = m.merchantkey 
        left join courier cour on r.entity_id = cour.courierkey 
    )
    where raw_permission_id = 301446
)
where rn between 1 and 100
order by roleCreated desc;

如果您自己運行內部查詢，您將看到每個role_id多個結果; 每個都有listagg組件，但也會包含（臨時）各個permission_id值，我將其別名為raw_permission_id 。

然后，下一個查詢可以過濾您感興趣的確切權限。對於單個權限，就像您在此處一樣，每個角色最多只能提供一行，但如果您正在查找其中一個范圍權限然后你可能會得到重復（如果一個角色匹配多個）。 因此，外部查詢排除raw_permission_id並添加distinct以抑制任何重復。