PHP-在第一個表中需要前3個json數據，在第二個表中需要所有數據

Question

我是PHP編程的初學者。我有一個代碼，我需要獲取第一個表中的前3個數據以及下一個表中的所有數據。數據來自db作為json。

以下是我的php文件

<?php 
    $host = "localhost"; 
    $user = "root"; 
    $pass = ""; 
    $database = "TMS_Sample"; 

    $linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host."); 
    mysql_select_db($database, $linkID) or die("Could not find database."); 


    $result = mysql_query("SELECT * FROM Completed_Training");
    while ($row = mysql_fetch_assoc($result)) {
        $array[] = $row;
    }
    echo json_encode($array);
?>

我得到以下json作為結果：

[{"Date":"2012-12- 04","Topic":"Collections","Trainer":"Prabhakaran.G","Status":"Invitation Sent"},{"Date":"2012-12-12","Topic":"Collections","Trainer":"Prabhakaran.G","Status":"Invitation Sent"},{"Date":"2012-12-07","Topic":"ffb","Trainer":"vcvxcv","Status":"cvxcv"},{"Date":"2012-12-08","Topic":"xcv","Trainer":"cvxcv","Status":"vxcv"},{"Date":"2012-12-09","Topic":"cvxcv","Trainer":"cvxcv","Status":"cvxcvxc"},{"Date":"2012-12-10","Topic":"xcv","Trainer":"vxcvxc","Status":"vxcv"},{"Date":"2012-12-11","Topic":"vv","Trainer":"vv","Status":"vxcv"},{"Date":"2012-12-12","Topic":"vv","Trainer":"vcv","Status":"cvxcv"},{"Date":"2012-12-13","Topic":"vv","Trainer":"cvxcv","Status":"cvv"},{"Date":"2012-12-14","Topic":"vxcv","Trainer":"vccv","Status":"xcvcv"},{"Date":"2012-12-14","Topic":"vcxvxc","Trainer":"cvxcv","Status":"cvxcv"},{"Date":"2012-12-15","Topic":"cvxcv","Trainer":"xcvxcv","Status":"xcvxcv"},{"Date":"2012-12-16","Topic":"sdasd","Trainer":"sdasd","Status":"dscxzc"},{"Date":"2012-12-16","Topic":"scxzcxzc","Trainer":"sdfscxzc","Status":"sadffcvzxc"},{"Date":"2012-12-17","Topic":"fxzcvxzc","Trainer":"zcvxzcz","Status":"xzcxzcxzcxz"},{"Date":"2012-12-18","Topic":"xzceafsdfv","Trainer":"vxvxv","Status":"xgsdfgvsd"},{"Date":"2012-12-12","Topic":"xcdvxvxcv","Trainer":"vxzdgvgSv","Status":"gbvsgv"},{"Date":"2012-12-27","Topic":"SDgvsdv","Trainer":"sdvsdv","Status":"sdgvsdv"},{"Date":"2012-12-11","Topic":"sdvsvd","Trainer":"sdvsdv","Status":"vdv"},{"Date":"2012-12-22","Topic":"dvsdv","Trainer":"vssdv","Status":"vsdvV"}]

現在，我需要在html表中顯示此json數據

我已經在1個表中顯示了所有數據。 但是我需要的是在第一個表中獲取前3個數據，在下一個表中獲取所有數據。

這是我的html代碼：

<!DOCTYPE HTML>
<html>
    <head>
        <script type="text/javascript" src="jquery182.js"></script>
        <script type="text/javascript" language="javascript">
            $(document).ready(function () {
                $.getJSON('CompletedTraining.php', null, function (data) {
                    var Completed_counter = 1;
                    if (data) {
                        if (Completed_counter <= 3) {
                            var table = '<table border="1">';
                            $.each(data, function (i, element) {
                                table += '<tr>';
                                table += '<td>' + element.Date + '</td>';
                                table += '<td>' + element.Topic + '</td>';
                                table += '<td>' + element.Trainer + '</td>';
                                table += '<td>' + element.Status + '</td>';
                                table += '</tr>';
                            });
                            table += '</table>';
                            $('#getname').html(table);
                        }

                        var table1 = '<table border="1">';
                        $.each(data, function (j, element1) {
                            table1 += '<tr>';
                            table1 += '<td>' + element1.Date + '</td>';
                            table1 += '<td>' + element1.Topic + '</td>';
                            table1 += '<td>' + element1.Trainer + '</td>';
                            table1 += '<td>' + element1.Status + '</td>';
                            table1 += '</tr>';
                        });
                        table1 += '</table>';
                        $('#getname1').html(table1);
                        Completed_counter = Completed_counter + 1;
                    } else {
                        alert("error");
                    }
                });
            });
        </script>
    </head>
    <body>
        <form name="index">
            <table id="getname" ></table>
            <table id="getname1" ></table>
        </form>
    </body>
</html>

Answer 1

我使它盡可能的簡單..以便於理解。

不需要循環兩次數據...使用$.each()函數一次..並檢查$.each函數中的條件

這是小提琴

http://jsfiddle.net/yXB3W/4/

更新

另一個小提琴

http://jsfiddle.net/yXB3W/7/

您已經有數據..所以您只需要檢查小提琴中if(data)...的代碼

PHP-在第一個表中需要前3個json數據，在第二個表中需要所有數據

問題描述

1 個解決方案

解決方案1
1 已采納 2012-12-14 08:45:14

PHP-在第一個表中需要前3個json數據，在第二個表中需要所有數據

問題描述

1 個解決方案

解決方案1 1 已采納 2012-12-14 08:45:14

解決方案1
1 已采納 2012-12-14 08:45:14