[UIView setText：]：無法識別的選擇器已發送到實例0x89625d0

Question

我試圖在視圖中添加自定義復選框...我在情節提要上繪制視圖，並借助名為UICheckbox的第三方代碼來訪問它。

UICheckbox.h

#import <UIKit/UIKit.h>

@interface UICheckbox : UIControl

-(void)setChecked:(BOOL)boolValue;
-(void)setDisabled:(BOOL)boolValue;
-(void)setText:(NSString *)stringValue;

@property(nonatomic, assign)BOOL checked;
@property(nonatomic, assign)BOOL disabled;
@property(nonatomic, strong)NSString *text;

@end

UICheckbox.m

#import "UICheckbox.h"

@interface UICheckbox (){
    BOOL loaded;
} 

@property(nonatomic, strong)UILabel *textLabel;

@end



@implementation UICheckbox
@synthesize checked = _checked;
@synthesize disabled = _disabled;
@synthesize text = _text;
@synthesize textLabel = _textLabel;

- (void)awakeFromNib {
    self.backgroundColor = [UIColor clearColor];
}

-(void)drawRect:(CGRect)rect {
    UIImage *image = [UIImage imageNamed:[NSString    stringWithFormat:@"uicheckbox_%@checked.png", (self.checked) ? @"" : @"un"]];
    [image drawInRect:CGRectMake(0, 0, self.frame.size.width, self.frame.size.height)];

    if(self.disabled) {
        self.userInteractionEnabled = FALSE;
        self.alpha = 0.7f;
    } else {
        self.userInteractionEnabled = TRUE;
        self.alpha = 1.0f;
    }

    if(self.text) {
        if(!loaded) {
            _textLabel = [[UILabel alloc] initWithFrame:CGRectMake(self.frame.size.width +  5, 0, 1024, 30)];
            _textLabel.backgroundColor = [UIColor clearColor];
            [self addSubview:_textLabel];

            loaded = TRUE;
        }

        _textLabel.text = self.text;
     }
}

-(BOOL)beginTrackingWithTouch:(UITouch *)touch withEvent:(UIEvent *)event {
    [self setChecked:!self.checked];
    return TRUE;
}

-(void)setChecked:(BOOL)boolValue {
    _checked = boolValue;
    [self setNeedsDisplay];
}

-(void)setDisabled:(BOOL)boolValue {
    _disabled = boolValue;
    [self setNeedsDisplay];
}

-(void)setText:(NSString *)stringValue {
    _text = stringValue;
    [self setNeedsDisplay];
}

@end

在我的viewDidLoad ...

self.checkbox.text = @"Want to get the updates directly";

我像這樣執行動作

-(IBAction)testCheckbox:(id)sender {
    NSLog(@"checkbox.checked = %@", (self.checkbox.checked) ? @"YES" : @"NO");
}

從情節提要的角度來看。...我排好出口，摸了摸各自的信息，並得到此錯誤。

請幫忙...

Answer 1

這很簡單，但是當我在代碼中更改插座類型時，我得到了完全相同的錯誤-看起來它仍連接在情節提要中，但事實並非如此。 我只需要將情節提要中的插座（例如，標簽）重新連接到代碼插座即可。 您不會考慮這一點，因為插座仍標記為已連接，但如果您進行了更改，則不會。