PHP正則表達式和URL解析

Question

如何使用PHP中的preg_replace來解析URL。

說我有網址

http://google.com?id=123

我想訪問網址的每個部分，這樣

echo $protocol;

會打印

http

要么

echo $domain;

會打印

google

和

echo $upperDomain;

版畫

com

最后，

echo $rest;

會打印

?id=123

Answer 1

有一個功能： parse_url（）

$url = 'http://google.com?id=123';    
print_r(parse_url($url));

打印：

Array
(
    [scheme] => http
    [host] => google.com
    [query] => id=123
)

Answer 2

來自文檔的parse_url（） ...

 mixed parse_url ( string $url [, int $component = -1 ] )

This function parses a URL and returns an associative array containing any of the   
various components of the URL that are present.

This function is not meant to validate the given URL, it only breaks it up into the 
above listed parts. Partial URLs are also accepted, parse_url() tries its best to   
parse them correctly.